OCR M2 2008 January — Question 5 9 marks

Exam BoardOCR
ModuleM2 (Mechanics 2)
Year2008
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeDirect collision with direction reversal
DifficultyStandard +0.3 This is a standard M2 collision problem requiring conservation of momentum and impulse calculations. Part (i) involves straightforward momentum conservation with algebraic manipulation, part (ii) is direct impulse-momentum application, and part (iii) uses the standard coefficient of restitution formula. All techniques are routine for M2 students with no novel problem-solving required, making it slightly easier than average.
Spec6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation6.03i Coefficient of restitution: e6.03k Newton's experimental law: direct impact

5 A particle \(P\) of mass \(2 m\) is moving on a smooth horizontal surface with speed \(u\) when it collides directly with a particle \(Q\) of mass \(k m\) whose speed is \(3 u\) in the opposite direction. As a result of the collision, the directions of motion of both particles are reversed and the speed of \(P\) is halved.
  1. Find, in terms of \(u\) and \(k\), the speed of \(Q\) after the collision. Hence write down the range of possible values of \(k\).
  2. Calculate the magnitude of the impulse which \(Q\) exerts on \(P\).
  3. Given that \(k = \frac { 1 } { 2 }\), calculate the coefficient of restitution between \(P\) and \(Q\). \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{982647bd-8514-40cf-b4ee-674f51df32c5-3_472_1143_221_242} \captionsetup{labelformat=empty} \caption{Fig. 1}
    \end{figure} One end of a light inextensible string is attached to a point \(P\). The other end is attached to a point \(Q , 1.96 \mathrm {~m}\) vertically below \(P\). A small smooth bead \(B\), of mass 0.3 kg , is threaded on the string and moves in a horizontal circle with centre \(Q\) and radius \(1.96 \mathrm {~m} . B\) rotates about \(Q\) with constant angular speed \(\omega\) rad s \(^ { - 1 }\) (see Fig. 1).

5 A particle $P$ of mass $2 m$ is moving on a smooth horizontal surface with speed $u$ when it collides directly with a particle $Q$ of mass $k m$ whose speed is $3 u$ in the opposite direction. As a result of the collision, the directions of motion of both particles are reversed and the speed of $P$ is halved.\\
(i) Find, in terms of $u$ and $k$, the speed of $Q$ after the collision. Hence write down the range of possible values of $k$.\\
(ii) Calculate the magnitude of the impulse which $Q$ exerts on $P$.\\
(iii) Given that $k = \frac { 1 } { 2 }$, calculate the coefficient of restitution between $P$ and $Q$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{982647bd-8514-40cf-b4ee-674f51df32c5-3_472_1143_221_242}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

One end of a light inextensible string is attached to a point $P$. The other end is attached to a point $Q , 1.96 \mathrm {~m}$ vertically below $P$. A small smooth bead $B$, of mass 0.3 kg , is threaded on the string and moves in a horizontal circle with centre $Q$ and radius $1.96 \mathrm {~m} . B$ rotates about $Q$ with constant angular speed $\omega$ rad s $^ { - 1 }$ (see Fig. 1).\\

\hfill \mbox{\textit{OCR M2 2008 Q5 [9]}}