CAIE FP2 2017 November — Question 7 7 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2017
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Distribution
TypeDerive CDF from PDF
DifficultyModerate -0.8 This is a straightforward application of standard exponential distribution formulas. Part (i) requires integrating the PDF to get CDF (a routine calculus exercise), while parts (ii) and (iii) involve direct substitution into the CDF. The exponential distribution is a core topic with well-practiced techniques, making this easier than average despite being Further Maths content.
Spec5.03a Continuous random variables: pdf and cdf5.03e Find cdf: by integration5.03f Relate pdf-cdf: medians and percentiles

7 The random variable \(X\) has probability density function f given by $$\mathrm { f } ( x ) = \begin{cases} 0.2 \mathrm { e } ^ { - 0.2 x } & x \geqslant 0 \\ 0 & \text { otherwise } \end{cases}$$
  1. Find the distribution function of \(X\).
  2. Find \(\mathrm { P } ( X > 2 )\).
  3. Find the median of \(X\).

Question 7(i):
AnswerMarks Guidance
\(F(x) = \int f(x)\,dx = -e^{-0.2x} + c = 1 - e^{-0.2x}\) \((x \geq 0)\)M1 State, or integrate and use \(F(0)=0\) or \(F(x) \to 1\) as \(x \to \infty\)
and \(F(x) = 0\) \((x < 0\) or otherwise\()\)A1 to find \(F(x)\) (A0 if case \(x < 0\) omitted)
Total: 2
Question 7(ii):
AnswerMarks Guidance
\(P(X > 2) = 1 - F(2) = e^{-0.4} = 0.670\)M1 A1 Find \(P(X > 2)\): (M0 for \(F(2)\))
Total: 3
Question 7(iii):
AnswerMarks Guidance
\(1 - e^{-0.2m} = \frac{1}{2}\), \(e^{0.2m} = 2\)M1 Find median value \(m\) from \(F(m)\) or \(1 - F(m) = \frac{1}{2}\)
\(m = 5\ln 2\) or \(3.47\)M1 A1
Total: 3
## Question 7(i):

$F(x) = \int f(x)\,dx = -e^{-0.2x} + c = 1 - e^{-0.2x}$ $(x \geq 0)$ | M1 | State, or integrate and use $F(0)=0$ or $F(x) \to 1$ as $x \to \infty$

and $F(x) = 0$ $(x < 0$ or otherwise$)$ | A1 | to find $F(x)$ (**A0** if case $x < 0$ omitted)

**Total: 2**

## Question 7(ii):

$P(X > 2) = 1 - F(2) = e^{-0.4} = 0.670$ | M1 A1 | Find $P(X > 2)$: (**M0** for $F(2)$)

**Total: 3**

## Question 7(iii):

$1 - e^{-0.2m} = \frac{1}{2}$, $e^{0.2m} = 2$ | M1 | Find median value $m$ from $F(m)$ or $1 - F(m) = \frac{1}{2}$

$m = 5\ln 2$ or $3.47$ | M1 A1 |

**Total: 3**

---
7 The random variable $X$ has probability density function f given by

$$\mathrm { f } ( x ) = \begin{cases} 0.2 \mathrm { e } ^ { - 0.2 x } & x \geqslant 0 \\ 0 & \text { otherwise } \end{cases}$$

(i) Find the distribution function of $X$.\\

(ii) Find $\mathrm { P } ( X > 2 )$.\\

(iii) Find the median of $X$.\\

\hfill \mbox{\textit{CAIE FP2 2017 Q7 [7]}}