CAIE P3 2007 November — Question 6 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2007
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFixed Point Iteration
TypeRearrange to iterative form
DifficultyModerate -0.3 This is a standard fixed-point iteration question with routine steps: sketch graphs to show unique root, verify interval, algebraically rearrange equation (straightforward manipulation), then apply given iterative formula. All techniques are textbook exercises requiring no novel insight, though the multi-part structure and iteration to convergence adds slight complexity beyond pure recall.
Spec1.07t Construct differential equations: in context1.08k Separable differential equations: dy/dx = f(x)g(y)

6
  1. By sketching a suitable pair of graphs, show that the equation $$2 - x = \ln x$$ has only one root.
  2. Verify by calculation that this root lies between 1.4 and 1.7.
  3. Show that this root also satisfies the equation $$x = \frac { 1 } { 3 } ( 4 + x - 2 \ln x )$$
  4. Use the iterative formula $$x _ { n + 1 } = \frac { 1 } { 3 } \left( 4 + x _ { n } - 2 \ln x _ { n } \right)$$ with initial value \(x _ { 1 } = 1.5\), to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

AnswerMarks Guidance
(i) Make a recognisable sketch of an appropriate graph, e.g. \(y = \ln x\)B1
Sketch an appropriate graph, e.g. \(y = 2 - x\), correctly and justify the given statementB1 [2]
(ii) Consider sign of \(2 - x - \ln x\) when \(x = 1.4\) and \(x = 1.7\), or equivalentM1
Complete the argument with correct calculationsA1 [2]
(iii) Rearrange the equation as \(x = \frac{1}{2}(4 + x - 2\ln x)\) as \(2 - x = \ln x\), or vice versaB1 [1]
(iv) Use the iterative formula correctly at least onceM1
Obtain final answer \(1.56\)A1
Show sufficient iterations to 4 d.p. to justify its accuracy to 2 d.p., or show there is a sign change in the interval \([1.555, 1.565]\)A1 [3]
**(i)** Make a recognisable sketch of an appropriate graph, e.g. $y = \ln x$ | B1 |
Sketch an appropriate graph, e.g. $y = 2 - x$, correctly and justify the given statement | B1 | [2]

**(ii)** Consider sign of $2 - x - \ln x$ when $x = 1.4$ and $x = 1.7$, or equivalent | M1 |
Complete the argument with correct calculations | A1 | [2]

**(iii)** Rearrange the equation as $x = \frac{1}{2}(4 + x - 2\ln x)$ as $2 - x = \ln x$, or vice versa | B1 | [1]

**(iv)** Use the iterative formula correctly at least once | M1 |
Obtain final answer $1.56$ | A1 |
Show sufficient iterations to 4 d.p. to justify its accuracy to 2 d.p., or show there is a sign change in the interval $[1.555, 1.565]$ | A1 | [3]
6 (i) By sketching a suitable pair of graphs, show that the equation

$$2 - x = \ln x$$

has only one root.\\
(ii) Verify by calculation that this root lies between 1.4 and 1.7.\\
(iii) Show that this root also satisfies the equation

$$x = \frac { 1 } { 3 } ( 4 + x - 2 \ln x )$$

(iv) Use the iterative formula

$$x _ { n + 1 } = \frac { 1 } { 3 } \left( 4 + x _ { n } - 2 \ln x _ { n } \right)$$

with initial value $x _ { 1 } = 1.5$, to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

\hfill \mbox{\textit{CAIE P3 2007 Q6 [8]}}