CAIE P3 2004 November — Question 4 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2004
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeSolve equation with tan(θ ± α)
DifficultyStandard +0.3 This is a straightforward application of the tan(A±B) addition formula followed by algebraic manipulation and solving a quadratic. Part (i) is guided ('show that'), requiring routine expansion and simplification. Part (ii) is direct quadratic formula application with domain restriction. Slightly easier than average due to the scaffolding and standard technique.
Spec1.05l Double angle formulae: and compound angle formulae1.05o Trigonometric equations: solve in given intervals

4
  1. Show that the equation $$\tan \left( 45 ^ { \circ } + x \right) = 2 \tan \left( 45 ^ { \circ } - x \right)$$ can be written in the form $$\tan ^ { 2 } x - 6 \tan x + 1 = 0$$
  2. Hence solve the equation \(\tan \left( 45 ^ { \circ } + x \right) = 2 \tan \left( 45 ^ { \circ } - x \right)\), for \(0 ^ { \circ } < x < 90 ^ { \circ }\).

AnswerMarks Guidance
(i) EITHER: Use \(\tan(A \pm B)\) formula correctly to obtain an equation in \(\tan x\)M1
State or imply the equation \(\frac{1+\tan x}{1-\tan x} = \frac{2(1-\tan x)}{1+\tan x}\) or equivalentA1
Transform to an expanded horizontal quadratic equation in \(\tan x\)M1
Obtain given answer correctlyA1
OR: Use \(\sin(A \pm B)\) and \(\cos(A \pm B)\) formulae correctly to obtain an equation in \(\sin x\) and \(\cos x\)M1
Using values of \(\sin 45°\) and \(\cos 45°\), or their equality, obtain an expanded horizontal equation in \(\sin x\) and \(\cos x\)A1
Transform to a quadratic equation in \(\tan x\)M1
Obtain given answer correctlyA1 Total: 4 marks
(ii) Solve the given quadratic and calculate an angle in degrees or radiansM1
Obtain one answer e.g. \(80.3°\)A1
Obtain second answer \(9.7°\) and no others in the rangeA1 [Ignore answers outside the given range.]
Total: 3 marks
**(i)** **EITHER:** Use $\tan(A \pm B)$ formula correctly to obtain an equation in $\tan x$ | M1 | |
State or imply the equation $\frac{1+\tan x}{1-\tan x} = \frac{2(1-\tan x)}{1+\tan x}$ or equivalent | A1 | |
Transform to an expanded horizontal quadratic equation in $\tan x$ | M1 | |
Obtain given answer correctly | A1 | |

**OR:** Use $\sin(A \pm B)$ and $\cos(A \pm B)$ formulae correctly to obtain an equation in $\sin x$ and $\cos x$ | M1 | |
Using values of $\sin 45°$ and $\cos 45°$, or their equality, obtain an expanded horizontal equation in $\sin x$ and $\cos x$ | A1 | |
Transform to a quadratic equation in $\tan x$ | M1 | |
Obtain given answer correctly | A1 | **Total: 4 marks** |

**(ii)** Solve the given quadratic and calculate an angle in degrees or radians | M1 | |
Obtain one answer e.g. $80.3°$ | A1 | |
Obtain second answer $9.7°$ and no others in the range | A1 | [Ignore answers outside the given range.] |
| | | **Total: 3 marks** |
4 (i) Show that the equation

$$\tan \left( 45 ^ { \circ } + x \right) = 2 \tan \left( 45 ^ { \circ } - x \right)$$

can be written in the form

$$\tan ^ { 2 } x - 6 \tan x + 1 = 0$$

(ii) Hence solve the equation $\tan \left( 45 ^ { \circ } + x \right) = 2 \tan \left( 45 ^ { \circ } - x \right)$, for $0 ^ { \circ } < x < 90 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P3 2004 Q4 [7]}}