CAIE FP2 2011 June — Question 7 8 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2011
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeometric Distribution
TypeFind minimum n for P(X ≤ n) > threshold
DifficultyModerate -0.3 This is a straightforward application of geometric distribution formulas with p=1/6. Parts (i) and (ii) require direct substitution into standard formulas, while part (iii) involves solving an inequality using logarithms—all routine techniques for Further Maths students with no novel problem-solving required.
Spec5.02g Geometric probabilities: P(X=r) = p(1-p)^(r-1)

7 A fair die is thrown until a 6 appears for the first time. Assuming that the throws are independent, find
  1. the probability that exactly 5 throws are needed,
  2. the probability that fewer than 8 throws are needed,
  3. the least integer \(n\) such that the probability of obtaining a 6 before the \(n\)th throw is at least 0.99 .

Question 7:
Part (i):
AnswerMarks Guidance
Working/AnswerMark Guidance
Find probability for needing 5 throws: \(p(1-p)^4\) with \(p = 1/6;\ = 0{\cdot}0804\)M1 A1; A1 [Subtotal: 3]
Part (ii):
AnswerMarks Guidance
Working/AnswerMark Guidance
Find probability for needing \(< 8\) throws: \(1 - (1-p)^7 = 0{\cdot}721\)M1 A1 [Subtotal: 2]
Part (iii):
AnswerMarks Guidance
Working/AnswerMark Guidance
Relate prob. to 0.99 (allow \(>\) but not \(=\)): \(1 - (1-p)^{n-1} \geq 0{\cdot}99\)B1
Find least integer \(n\): \((n-1)\log\frac{5}{6} \leq \log 0{\cdot}01\)M1
(Allow M1 A1 even if equality used): \(n - 1 \geq 25{\cdot}3,\ n_{min} = 27\)A1 [Subtotal: 3]
Total: 8
## Question 7:

### Part (i):
| Working/Answer | Mark | Guidance |
|---|---|---|
| Find probability for needing 5 throws: $p(1-p)^4$ with $p = 1/6;\ = 0{\cdot}0804$ | M1 A1; A1 | [Subtotal: 3] |

### Part (ii):
| Working/Answer | Mark | Guidance |
|---|---|---|
| Find probability for needing $< 8$ throws: $1 - (1-p)^7 = 0{\cdot}721$ | M1 A1 | [Subtotal: 2] |

### Part (iii):
| Working/Answer | Mark | Guidance |
|---|---|---|
| Relate prob. to 0.99 (allow $>$ but not $=$): $1 - (1-p)^{n-1} \geq 0{\cdot}99$ | B1 | |
| Find least integer $n$: $(n-1)\log\frac{5}{6} \leq \log 0{\cdot}01$ | M1 | |
| (Allow M1 A1 even if equality used): $n - 1 \geq 25{\cdot}3,\ n_{min} = 27$ | A1 | [Subtotal: 3] |

**Total: 8**

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7 A fair die is thrown until a 6 appears for the first time. Assuming that the throws are independent, find\\
(i) the probability that exactly 5 throws are needed,\\
(ii) the probability that fewer than 8 throws are needed,\\
(iii) the least integer $n$ such that the probability of obtaining a 6 before the $n$th throw is at least 0.99 .

\hfill \mbox{\textit{CAIE FP2 2011 Q7 [8]}}