CAIE FP2 2010 June — Question 11 OR

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeSample size determination
DifficultyChallenging +1.2 This is a standard application of the Central Limit Theorem requiring students to work with sums of normal random variables, find probabilities using normal approximation, determine sample sizes from probability constraints, and compare two independent normal distributions. While it involves multiple parts and requires careful setup of the difference of two normals in part (c), each step follows well-established procedures taught in Further Statistics without requiring novel insight or complex problem-solving beyond textbook methods.
Spec5.01a Permutations and combinations: evaluate probabilities5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

Aram is a packer at a supermarket checkout and the time he takes to pack a randomly chosen item has mean 1.5 s and standard deviation 0.4 s . Justifying any approximation that you make, find the probability that Aram will pack 50 randomly chosen items in less than 70 s . Find the greatest number of items that Aram could pack within 70 s with probability at least \(90 \%\). Huldu is also a packer at the supermarket. The time that she takes to pack a randomly chosen item has mean 1.3 s and standard deviation 0.5 s . Aram and Huldu each have 50 items to pack. Find the probability that Huldu takes a shorter time than Aram.

Question 11:
AnswerMarks Guidance
Answer/WorkingMark Guidance
*EITHER:* Find 2 indep. eqns for \(R_B\), \(F_B\) only:M1
Moments for \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\)M1 A1
Moments for system about \(C\): \(F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta\)M1 A1
Add equations to find \(F_B\): \(F_B = 5W/4\) A.G.M1 A1
*OR:* If \(R_C\), \(F_C\) introduced, resolve vertically: \(F_B + F_C = 3W\)(B1)
Any 2 moment eqns indep. of above resln. e.g.:
For \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\)
For \(CA\) about \(A\): \(F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta\)
For system about \(B\): \(F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta\)
(2 system eqns are equiv. to vert. resolution)\((2\times\) M1 A1)
Solve eqns using \(R_B = R_C\) to find \(F_B\): \(F_B = 5W/4\) A.G.(M1 A1)
Find \(F_C\) by eg vertical resolution for rods: \(F_C = 7W/4\)B1
Find \(R_B\) [or \(R_C\)] from a moment eqn: \(R_B\,[= R_C] = \frac{3}{4}W\tan\beta\)B1
Find one of \(F_B/R_B\), \(F_C/R_C\) eg: \(F_B/R_B = 5/(3\tan\beta)\)M1 A1
Find other eg: \(F_C/R_C = 7/(3\tan\beta)\)A1
Find set of possible values of \(\mu\): \(\mu > 7/(3\tan\beta)\) (allow \(\geq\))M1 A1 Total: 14
Question 11:
Part 1 (4 marks) - Finding P(T₅₀ < 70)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(T_{50}) = 50 \times 1.5 = 75\) and \(\text{Var}(T_{50}) = 50 \times 0.4^2 = 8\)B1 Both required
By central limit theorem *or* since \(n\) [or 50] is largeB1 State valid justification (A.E.F.)
\(\Phi\left(\frac{70-75}{\sqrt{8}}\right)\)M1 Find Normal approximation to \(P(T_{50} < 70)\)
\(= 1 - \Phi(1.768) = 0.0385 \pm 0.0001\)A1
Part 2 (6 marks) - Finding maximum n such that P(Tₙ < 70) > 0.9
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(T_n) = 1.5n\) and \(\text{Var}(T_n) = 0.4^2 n\)B1 Both required
\(\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9\)M1 Use Normal approximation for \(P(T_n < 70) > 0.9\)
\(\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282\)A1 Invert function
\((\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0\)M1 Rearrange as quadratic expression in \(\sqrt{n}\)
\(44.4\)A1 Find positive root when expression is zero
\(n_{max} = 44\)A1 Find greatest integer value of \(n\)
Part 3 (4 marks) - Finding P(A - H > 0)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(A-H) = 75 - 65 = 10\) and \(\text{Var}(A-H) = 8 + 12.5 = 20.5\)M1 A1 For difference in times, find \(E(A-H)\) and \(\text{Var}(A-H)\)
\(\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986\)M1 A1 Find Normal approximation to \(P(A-H>0)\)
Total: [14]
## Question 11:

| Answer/Working | Mark | Guidance |
|---|---|---|
| *EITHER:* Find 2 indep. eqns for $R_B$, $F_B$ only: | M1 | |
| Moments for $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | M1 A1 | |
| Moments for system about $C$: $F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta$ | M1 A1 | |
| Add equations to find $F_B$: $F_B = 5W/4$ **A.G.** | M1 A1 | |
| *OR:* If $R_C$, $F_C$ introduced, resolve vertically: $F_B + F_C = 3W$ | (B1) | |
| Any 2 moment eqns indep. of above resln. e.g.: | | |
| For $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | | |
| For $CA$ about $A$: $F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta$ | | |
| For system about $B$: $F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta$ | | |
| (2 system eqns are equiv. to vert. resolution) | $(2\times$ M1 A1) | |
| Solve eqns using $R_B = R_C$ to find $F_B$: $F_B = 5W/4$ **A.G.** | (M1 A1) | |
| Find $F_C$ by eg vertical resolution for rods: $F_C = 7W/4$ | B1 | |
| Find $R_B$ [or $R_C$] from a moment eqn: $R_B\,[= R_C] = \frac{3}{4}W\tan\beta$ | B1 | |
| Find one of $F_B/R_B$, $F_C/R_C$ eg: $F_B/R_B = 5/(3\tan\beta)$ | M1 A1 | |
| Find other eg: $F_C/R_C = 7/(3\tan\beta)$ | A1 | |
| Find set of possible values of $\mu$: $\mu > 7/(3\tan\beta)$ (allow $\geq$) | M1 A1 | **Total: 14** |

# Question 11:

## Part 1 (4 marks) - Finding P(T₅₀ < 70)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_{50}) = 50 \times 1.5 = 75$ and $\text{Var}(T_{50}) = 50 \times 0.4^2 = 8$ | B1 | Both required |
| By central limit theorem *or* since $n$ [or 50] is large | B1 | State valid justification (A.E.F.) |
| $\Phi\left(\frac{70-75}{\sqrt{8}}\right)$ | M1 | Find Normal approximation to $P(T_{50} < 70)$ |
| $= 1 - \Phi(1.768) = 0.0385 \pm 0.0001$ | A1 | |

## Part 2 (6 marks) - Finding maximum n such that P(Tₙ < 70) > 0.9

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_n) = 1.5n$ and $\text{Var}(T_n) = 0.4^2 n$ | B1 | Both required |
| $\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9$ | M1 | Use Normal approximation for $P(T_n < 70) > 0.9$ |
| $\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282$ | A1 | Invert function |
| $(\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0$ | M1 | Rearrange as quadratic expression in $\sqrt{n}$ |
| $44.4$ | A1 | Find positive root when expression is zero |
| $n_{max} = 44$ | A1 | Find greatest integer value of $n$ |

## Part 3 (4 marks) - Finding P(A - H > 0)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(A-H) = 75 - 65 = 10$ and $\text{Var}(A-H) = 8 + 12.5 = 20.5$ | M1 A1 | For difference in times, find $E(A-H)$ and $\text{Var}(A-H)$ |
| $\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986$ | M1 A1 | Find Normal approximation to $P(A-H>0)$ |

**Total: [14]**
Aram is a packer at a supermarket checkout and the time he takes to pack a randomly chosen item has mean 1.5 s and standard deviation 0.4 s . Justifying any approximation that you make, find the probability that Aram will pack 50 randomly chosen items in less than 70 s .

Find the greatest number of items that Aram could pack within 70 s with probability at least $90 \%$.

Huldu is also a packer at the supermarket. The time that she takes to pack a randomly chosen item has mean 1.3 s and standard deviation 0.5 s . Aram and Huldu each have 50 items to pack. Find the probability that Huldu takes a shorter time than Aram.

\hfill \mbox{\textit{CAIE FP2 2010 Q11 OR}}