CAIE FP2 2010 June — Question 11 EITHER

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2010
SessionJune
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeTwo jointed rods in equilibrium
DifficultyChallenging +1.2 This is a standard two-rod equilibrium problem requiring systematic application of equilibrium conditions (forces and moments) at multiple points. While it involves several steps and careful bookkeeping of forces at three contact points (B, hinge A, and C), the methodology is straightforward: resolve forces, take moments about strategic points, and apply friction constraints. The first part is guided (show a given result), and the second part requires combining inequalities from friction limits at both walls. This is typical Further Maths mechanics content, more involved than basic A-level but following standard procedures without requiring novel geometric insight.
Spec6.04e Rigid body equilibrium: coplanar forces

\includegraphics[max width=\textwidth, alt={}]{f6887893-66c5-40df-ba8d-9439a5c268eb-5_456_615_1210_765}
Two uniform rods \(A B\) and \(A C\) have lengths \(2 a\) and \(4 a\) and weights \(W\) and \(2 W\) respectively. They are freely hinged together at \(A\) and rest in equilibrium in a vertical plane with \(B\) and \(C\) in contact with two rough parallel vertical walls. The plane containing the rods is perpendicular to the walls. The rods \(A B\) and \(A C\) each make an angle \(\beta\) with the vertical (see diagram). Show that the magnitude of the frictional force acting on \(A B\) at \(B\) is \(\frac { 5 } { 4 } W\). Given that the coefficient of friction at \(B\) and at \(C\) is \(\mu\), find the set of possible values of \(\mu\) in terms of \(\beta\).

Question 11:
AnswerMarks Guidance
Answer/WorkingMark Guidance
*EITHER:* Find 2 indep. eqns for \(R_B\), \(F_B\) only:M1
Moments for \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\)M1 A1
Moments for system about \(C\): \(F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta\)M1 A1
Add equations to find \(F_B\): \(F_B = 5W/4\) A.G.M1 A1
*OR:* If \(R_C\), \(F_C\) introduced, resolve vertically: \(F_B + F_C = 3W\)(B1)
Any 2 moment eqns indep. of above resln. e.g.:
For \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\)
For \(CA\) about \(A\): \(F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta\)
For system about \(B\): \(F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta\)
(2 system eqns are equiv. to vert. resolution)\((2\times\) M1 A1)
Solve eqns using \(R_B = R_C\) to find \(F_B\): \(F_B = 5W/4\) A.G.(M1 A1)
Find \(F_C\) by eg vertical resolution for rods: \(F_C = 7W/4\)B1
Find \(R_B\) [or \(R_C\)] from a moment eqn: \(R_B\,[= R_C] = \frac{3}{4}W\tan\beta\)B1
Find one of \(F_B/R_B\), \(F_C/R_C\) eg: \(F_B/R_B = 5/(3\tan\beta)\)M1 A1
Find other eg: \(F_C/R_C = 7/(3\tan\beta)\)A1
Find set of possible values of \(\mu\): \(\mu > 7/(3\tan\beta)\) (allow \(\geq\))M1 A1 Total: 14
Question 11:
Part 1 (4 marks) - Finding P(T₅₀ < 70)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(T_{50}) = 50 \times 1.5 = 75\) and \(\text{Var}(T_{50}) = 50 \times 0.4^2 = 8\)B1 Both required
By central limit theorem *or* since \(n\) [or 50] is largeB1 State valid justification (A.E.F.)
\(\Phi\left(\frac{70-75}{\sqrt{8}}\right)\)M1 Find Normal approximation to \(P(T_{50} < 70)\)
\(= 1 - \Phi(1.768) = 0.0385 \pm 0.0001\)A1
Part 2 (6 marks) - Finding maximum n such that P(Tₙ < 70) > 0.9
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(T_n) = 1.5n\) and \(\text{Var}(T_n) = 0.4^2 n\)B1 Both required
\(\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9\)M1 Use Normal approximation for \(P(T_n < 70) > 0.9\)
\(\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282\)A1 Invert function
\((\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0\)M1 Rearrange as quadratic expression in \(\sqrt{n}\)
\(44.4\)A1 Find positive root when expression is zero
\(n_{max} = 44\)A1 Find greatest integer value of \(n\)
Part 3 (4 marks) - Finding P(A - H > 0)
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(E(A-H) = 75 - 65 = 10\) and \(\text{Var}(A-H) = 8 + 12.5 = 20.5\)M1 A1 For difference in times, find \(E(A-H)\) and \(\text{Var}(A-H)\)
\(\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986\)M1 A1 Find Normal approximation to \(P(A-H>0)\)
Total: [14]
## Question 11:

| Answer/Working | Mark | Guidance |
|---|---|---|
| *EITHER:* Find 2 indep. eqns for $R_B$, $F_B$ only: | M1 | |
| Moments for $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | M1 A1 | |
| Moments for system about $C$: $F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta$ | M1 A1 | |
| Add equations to find $F_B$: $F_B = 5W/4$ **A.G.** | M1 A1 | |
| *OR:* If $R_C$, $F_C$ introduced, resolve vertically: $F_B + F_C = 3W$ | (B1) | |
| Any 2 moment eqns indep. of above resln. e.g.: | | |
| For $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | | |
| For $CA$ about $A$: $F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta$ | | |
| For system about $B$: $F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta$ | | |
| (2 system eqns are equiv. to vert. resolution) | $(2\times$ M1 A1) | |
| Solve eqns using $R_B = R_C$ to find $F_B$: $F_B = 5W/4$ **A.G.** | (M1 A1) | |
| Find $F_C$ by eg vertical resolution for rods: $F_C = 7W/4$ | B1 | |
| Find $R_B$ [or $R_C$] from a moment eqn: $R_B\,[= R_C] = \frac{3}{4}W\tan\beta$ | B1 | |
| Find one of $F_B/R_B$, $F_C/R_C$ eg: $F_B/R_B = 5/(3\tan\beta)$ | M1 A1 | |
| Find other eg: $F_C/R_C = 7/(3\tan\beta)$ | A1 | |
| Find set of possible values of $\mu$: $\mu > 7/(3\tan\beta)$ (allow $\geq$) | M1 A1 | **Total: 14** |

# Question 11:

## Part 1 (4 marks) - Finding P(T₅₀ < 70)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_{50}) = 50 \times 1.5 = 75$ and $\text{Var}(T_{50}) = 50 \times 0.4^2 = 8$ | B1 | Both required |
| By central limit theorem *or* since $n$ [or 50] is large | B1 | State valid justification (A.E.F.) |
| $\Phi\left(\frac{70-75}{\sqrt{8}}\right)$ | M1 | Find Normal approximation to $P(T_{50} < 70)$ |
| $= 1 - \Phi(1.768) = 0.0385 \pm 0.0001$ | A1 | |

## Part 2 (6 marks) - Finding maximum n such that P(Tₙ < 70) > 0.9

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_n) = 1.5n$ and $\text{Var}(T_n) = 0.4^2 n$ | B1 | Both required |
| $\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9$ | M1 | Use Normal approximation for $P(T_n < 70) > 0.9$ |
| $\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282$ | A1 | Invert function |
| $(\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0$ | M1 | Rearrange as quadratic expression in $\sqrt{n}$ |
| $44.4$ | A1 | Find positive root when expression is zero |
| $n_{max} = 44$ | A1 | Find greatest integer value of $n$ |

## Part 3 (4 marks) - Finding P(A - H > 0)

| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(A-H) = 75 - 65 = 10$ and $\text{Var}(A-H) = 8 + 12.5 = 20.5$ | M1 A1 | For difference in times, find $E(A-H)$ and $\text{Var}(A-H)$ |
| $\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986$ | M1 A1 | Find Normal approximation to $P(A-H>0)$ |

**Total: [14]**
\begin{center}
\includegraphics[max width=\textwidth, alt={}]{f6887893-66c5-40df-ba8d-9439a5c268eb-5_456_615_1210_765}
\end{center}

Two uniform rods $A B$ and $A C$ have lengths $2 a$ and $4 a$ and weights $W$ and $2 W$ respectively. They are freely hinged together at $A$ and rest in equilibrium in a vertical plane with $B$ and $C$ in contact with two rough parallel vertical walls. The plane containing the rods is perpendicular to the walls. The rods $A B$ and $A C$ each make an angle $\beta$ with the vertical (see diagram). Show that the magnitude of the frictional force acting on $A B$ at $B$ is $\frac { 5 } { 4 } W$.

Given that the coefficient of friction at $B$ and at $C$ is $\mu$, find the set of possible values of $\mu$ in terms of $\beta$.

\hfill \mbox{\textit{CAIE FP2 2010 Q11 EITHER}}