| Exam Board | CAIE |
|---|---|
| Module | FP2 (Further Pure Mathematics 2) |
| Year | 2010 |
| Session | June |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Moments |
| Type | Two jointed rods in equilibrium |
| Difficulty | Challenging +1.2 This is a standard two-rod equilibrium problem requiring systematic application of equilibrium conditions (forces and moments) at multiple points. While it involves several steps and careful bookkeeping of forces at three contact points (B, hinge A, and C), the methodology is straightforward: resolve forces, take moments about strategic points, and apply friction constraints. The first part is guided (show a given result), and the second part requires combining inequalities from friction limits at both walls. This is typical Further Maths mechanics content, more involved than basic A-level but following standard procedures without requiring novel geometric insight. |
| Spec | 6.04e Rigid body equilibrium: coplanar forces |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| *EITHER:* Find 2 indep. eqns for \(R_B\), \(F_B\) only: | M1 | |
| Moments for \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\) | M1 A1 | |
| Moments for system about \(C\): \(F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta\) | M1 A1 | |
| Add equations to find \(F_B\): \(F_B = 5W/4\) A.G. | M1 A1 | |
| *OR:* If \(R_C\), \(F_C\) introduced, resolve vertically: \(F_B + F_C = 3W\) | (B1) | |
| Any 2 moment eqns indep. of above resln. e.g.: | ||
| For \(BA\) about \(A\): \(F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta\) | ||
| For \(CA\) about \(A\): \(F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta\) | ||
| For system about \(B\): \(F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta\) | ||
| (2 system eqns are equiv. to vert. resolution) | \((2\times\) M1 A1) | |
| Solve eqns using \(R_B = R_C\) to find \(F_B\): \(F_B = 5W/4\) A.G. | (M1 A1) | |
| Find \(F_C\) by eg vertical resolution for rods: \(F_C = 7W/4\) | B1 | |
| Find \(R_B\) [or \(R_C\)] from a moment eqn: \(R_B\,[= R_C] = \frac{3}{4}W\tan\beta\) | B1 | |
| Find one of \(F_B/R_B\), \(F_C/R_C\) eg: \(F_B/R_B = 5/(3\tan\beta)\) | M1 A1 | |
| Find other eg: \(F_C/R_C = 7/(3\tan\beta)\) | A1 | |
| Find set of possible values of \(\mu\): \(\mu > 7/(3\tan\beta)\) (allow \(\geq\)) | M1 A1 | Total: 14 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(E(T_{50}) = 50 \times 1.5 = 75\) and \(\text{Var}(T_{50}) = 50 \times 0.4^2 = 8\) | B1 | Both required |
| By central limit theorem *or* since \(n\) [or 50] is large | B1 | State valid justification (A.E.F.) |
| \(\Phi\left(\frac{70-75}{\sqrt{8}}\right)\) | M1 | Find Normal approximation to \(P(T_{50} < 70)\) |
| \(= 1 - \Phi(1.768) = 0.0385 \pm 0.0001\) | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(E(T_n) = 1.5n\) and \(\text{Var}(T_n) = 0.4^2 n\) | B1 | Both required |
| \(\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9\) | M1 | Use Normal approximation for \(P(T_n < 70) > 0.9\) |
| \(\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282\) | A1 | Invert function |
| \((\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0\) | M1 | Rearrange as quadratic expression in \(\sqrt{n}\) |
| \(44.4\) | A1 | Find positive root when expression is zero |
| \(n_{max} = 44\) | A1 | Find greatest integer value of \(n\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(E(A-H) = 75 - 65 = 10\) and \(\text{Var}(A-H) = 8 + 12.5 = 20.5\) | M1 A1 | For difference in times, find \(E(A-H)\) and \(\text{Var}(A-H)\) |
| \(\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986\) | M1 A1 | Find Normal approximation to \(P(A-H>0)\) |
## Question 11:
| Answer/Working | Mark | Guidance |
|---|---|---|
| *EITHER:* Find 2 indep. eqns for $R_B$, $F_B$ only: | M1 | |
| Moments for $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | M1 A1 | |
| Moments for system about $C$: $F_B\cdot 6a\sin\beta + R_B\cdot 2a\cos\beta = 9Wa\sin\beta$ | M1 A1 | |
| Add equations to find $F_B$: $F_B = 5W/4$ **A.G.** | M1 A1 | |
| *OR:* If $R_C$, $F_C$ introduced, resolve vertically: $F_B + F_C = 3W$ | (B1) | |
| Any 2 moment eqns indep. of above resln. e.g.: | | |
| For $BA$ about $A$: $F_B\cdot 2a\sin\beta - R_B\cdot 2a\cos\beta = Wa\sin\beta$ | | |
| For $CA$ about $A$: $F_C\cdot 4a\sin\beta - R_C\cdot 4a\cos\beta = 4Wa\sin\beta$ | | |
| For system about $B$: $F_C\cdot 6a\sin\beta - R_C\cdot 2a\cos\beta = 9Wa\sin\beta$ | | |
| (2 system eqns are equiv. to vert. resolution) | $(2\times$ M1 A1) | |
| Solve eqns using $R_B = R_C$ to find $F_B$: $F_B = 5W/4$ **A.G.** | (M1 A1) | |
| Find $F_C$ by eg vertical resolution for rods: $F_C = 7W/4$ | B1 | |
| Find $R_B$ [or $R_C$] from a moment eqn: $R_B\,[= R_C] = \frac{3}{4}W\tan\beta$ | B1 | |
| Find one of $F_B/R_B$, $F_C/R_C$ eg: $F_B/R_B = 5/(3\tan\beta)$ | M1 A1 | |
| Find other eg: $F_C/R_C = 7/(3\tan\beta)$ | A1 | |
| Find set of possible values of $\mu$: $\mu > 7/(3\tan\beta)$ (allow $\geq$) | M1 A1 | **Total: 14** |
# Question 11:
## Part 1 (4 marks) - Finding P(T₅₀ < 70)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_{50}) = 50 \times 1.5 = 75$ and $\text{Var}(T_{50}) = 50 \times 0.4^2 = 8$ | B1 | Both required |
| By central limit theorem *or* since $n$ [or 50] is large | B1 | State valid justification (A.E.F.) |
| $\Phi\left(\frac{70-75}{\sqrt{8}}\right)$ | M1 | Find Normal approximation to $P(T_{50} < 70)$ |
| $= 1 - \Phi(1.768) = 0.0385 \pm 0.0001$ | A1 | |
## Part 2 (6 marks) - Finding maximum n such that P(Tₙ < 70) > 0.9
| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(T_n) = 1.5n$ and $\text{Var}(T_n) = 0.4^2 n$ | B1 | Both required |
| $\Phi\left(\frac{70 - 1.5n}{0.4\sqrt{n}}\right) \geq 0.9$ | M1 | Use Normal approximation for $P(T_n < 70) > 0.9$ |
| $\frac{70 - 1.5n}{0.4\sqrt{n}} \geq 1.282$ | A1 | Invert function |
| $(\sqrt{n})^2 + 0.3419\sqrt{n} - \frac{140}{3} \leq 0$ | M1 | Rearrange as quadratic expression in $\sqrt{n}$ |
| $44.4$ | A1 | Find positive root when expression is zero |
| $n_{max} = 44$ | A1 | Find greatest integer value of $n$ |
## Part 3 (4 marks) - Finding P(A - H > 0)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $E(A-H) = 75 - 65 = 10$ and $\text{Var}(A-H) = 8 + 12.5 = 20.5$ | M1 A1 | For difference in times, find $E(A-H)$ and $\text{Var}(A-H)$ |
| $\Phi\left(\frac{10}{\sqrt{20.5}}\right) = \Phi(2.209) = 0.986$ | M1 A1 | Find Normal approximation to $P(A-H>0)$ |
**Total: [14]**
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\end{center}
Two uniform rods $A B$ and $A C$ have lengths $2 a$ and $4 a$ and weights $W$ and $2 W$ respectively. They are freely hinged together at $A$ and rest in equilibrium in a vertical plane with $B$ and $C$ in contact with two rough parallel vertical walls. The plane containing the rods is perpendicular to the walls. The rods $A B$ and $A C$ each make an angle $\beta$ with the vertical (see diagram). Show that the magnitude of the frictional force acting on $A B$ at $B$ is $\frac { 5 } { 4 } W$.
Given that the coefficient of friction at $B$ and at $C$ is $\mu$, find the set of possible values of $\mu$ in terms of $\beta$.
\hfill \mbox{\textit{CAIE FP2 2010 Q11 EITHER}}