OCR FP2 2011 January — Question 6 10 marks

Exam BoardOCR
ModuleFP2 (Further Pure Mathematics 2)
Year2011
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeRectangle bounds for definite integral
DifficultyStandard +0.3 This is a straightforward application of rectangular bounds for integration. Part (i) is routine calculus with logarithmic differentiation. Parts (ii)-(iv) involve standard lower/upper bound techniques using rectangles, requiring only careful arithmetic and understanding of the basic principle that rectangles below the curve give lower bounds. The function x^x adds mild interest but the actual work is mechanical calculation and diagram sketching—slightly easier than average A-level.
Spec1.06b Gradient of e^(kx): derivative and exponential model1.07g Differentiation from first principles: for small positive integer powers of x4.08g Derivatives: inverse trig and hyperbolic functions

6 \includegraphics[max width=\textwidth, alt={}, center]{debf6581-25ff-4692-bdfb-154675a3cdb0-3_608_1134_258_504} The diagram shows the curve \(y = \mathrm { f } ( x )\), defined by $$f ( x ) = \begin{cases} x ^ { x } & \text { for } 0 < x \leqslant 1 , \\ 1 & \text { for } x = 0 . \end{cases}$$
  1. By first taking logarithms, show that the curve has a stationary point at \(x = \mathrm { e } ^ { - 1 }\). The area under the curve from \(x = 0.5\) to \(x = 1\) is denoted by \(A\).
  2. By considering the set of three rectangles shown in the diagram, show that a lower bound for \(A\) is 0.388 .
  3. By considering another set of three rectangles, find an upper bound for \(A\), giving 3 decimal places in your answer. The area under the curve from \(x = 0\) to \(x = 0.5\) is denoted by \(B\).
  4. Draw a diagram to show rectangles which could be used to find lower and upper bounds for \(B\), using not more than three rectangles for each bound. (You are not required to find the bounds.)

Question 6(i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y=x^x \Rightarrow \ln y = x\ln x \Rightarrow \frac{1}{y}\frac{dy}{dx}=1+\ln x\)M1 For differentiating \(\ln y\) OR \(x\ln x\) w.r.t. \(x\)
\(\frac{dy}{dx}=x^x(1+\ln x)=0 \Rightarrow \ln x=-1 \Rightarrow x=e^{-1}\)A1 For \((1+\ln x)\) seen or implied
A1 3For correct \(x\)-value from fully correct working AG
Question 6(ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(A > 0.2\times0.5^{0.5}+0.2\times0.7^{0.7}+0.1\times0.9^{0.9}\)M1 For areas of 3 lower rectangles
\(\Rightarrow A > 0.3881(858) > 0.388\)A1 2 For lower bound rounding to AG
Question 6(iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(A < 0.2\times0.7^{0.7}+0.2\times0.9^{0.9}+0.1\times1^1\)M1 For areas of 3 upper rectangles
\(\Rightarrow A < 0.4377(177) < 0.438\)A1 2 For upper bound rounding to 0.438
Question 6(iv):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
[Sketch with lower rectangles]M1 Consider rectangle of height \(f(e^{-1})\)
A1Use at least 1 lower rectangle, height \(f(e^{-1})\)
[Sketch with upper rectangles]B1 3 Use at least 1 upper rectangle, height \(f(0)\)
SR If more than one rectangle is used for either bound, they must be shown correctly
## Question 6(i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $y=x^x \Rightarrow \ln y = x\ln x \Rightarrow \frac{1}{y}\frac{dy}{dx}=1+\ln x$ | M1 | For differentiating $\ln y$ OR $x\ln x$ w.r.t. $x$ |
| $\frac{dy}{dx}=x^x(1+\ln x)=0 \Rightarrow \ln x=-1 \Rightarrow x=e^{-1}$ | A1 | For $(1+\ln x)$ seen or implied |
| | A1 **3** | For correct $x$-value from fully correct working **AG** |

## Question 6(ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $A > 0.2\times0.5^{0.5}+0.2\times0.7^{0.7}+0.1\times0.9^{0.9}$ | M1 | For areas of 3 lower rectangles |
| $\Rightarrow A > 0.3881(858) > 0.388$ | A1 **2** | For lower bound rounding to **AG** |

## Question 6(iii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $A < 0.2\times0.7^{0.7}+0.2\times0.9^{0.9}+0.1\times1^1$ | M1 | For areas of 3 upper rectangles |
| $\Rightarrow A < 0.4377(177) < 0.438$ | A1 **2** | For upper bound rounding to 0.438 |

## Question 6(iv):

| Answer/Working | Marks | Guidance |
|---|---|---|
| [Sketch with lower rectangles] | M1 | Consider rectangle of height $f(e^{-1})$ |
| | A1 | Use at least 1 lower rectangle, height $f(e^{-1})$ |
| [Sketch with upper rectangles] | B1 **3** | Use at least 1 upper rectangle, height $f(0)$ |
| **SR** If more than one rectangle is used for either bound, they must be shown correctly | | |

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6\\
\includegraphics[max width=\textwidth, alt={}, center]{debf6581-25ff-4692-bdfb-154675a3cdb0-3_608_1134_258_504}

The diagram shows the curve $y = \mathrm { f } ( x )$, defined by

$$f ( x ) = \begin{cases} x ^ { x } & \text { for } 0 < x \leqslant 1 , \\ 1 & \text { for } x = 0 . \end{cases}$$

(i) By first taking logarithms, show that the curve has a stationary point at $x = \mathrm { e } ^ { - 1 }$.

The area under the curve from $x = 0.5$ to $x = 1$ is denoted by $A$.\\
(ii) By considering the set of three rectangles shown in the diagram, show that a lower bound for $A$ is 0.388 .\\
(iii) By considering another set of three rectangles, find an upper bound for $A$, giving 3 decimal places in your answer.

The area under the curve from $x = 0$ to $x = 0.5$ is denoted by $B$.\\
(iv) Draw a diagram to show rectangles which could be used to find lower and upper bounds for $B$, using not more than three rectangles for each bound. (You are not required to find the bounds.)

\hfill \mbox{\textit{OCR FP2 2011 Q6 [10]}}