OCR FP2 2011 January — Question 3 9 marks

Exam BoardOCR
ModuleFP2 (Further Pure Mathematics 2)
Year2011
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPolar coordinates
TypeSketch polar curve
DifficultyStandard +0.3 This is a straightforward multi-part question on curve sketching and function analysis. Parts involve identifying an asymptote (y=0, routine), finding range using calculus or completing the square (standard technique), and analyzing y²=f(x) which requires recognizing symmetry and domain restrictions. All parts are direct applications of standard A-level techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.02n Sketch curves: simple equations including polynomials1.02u Functions: definition and vocabulary (domain, range, mapping)1.07n Stationary points: find maxima, minima using derivatives

3 The function f is defined by \(\mathrm { f } ( x ) = \frac { 5 a x } { x ^ { 2 } + a ^ { 2 } }\), for \(x \in \mathbb { R }\) and \(a > 0\).
  1. For the curve with equation \(y = \mathrm { f } ( x )\),
    1. write down the equation of the asymptote,
    2. find the range of values that \(y\) can take.
    3. For the curve with equation \(y ^ { 2 } = \mathrm { f } ( x )\), write down
      (a) the equation of the line of symmetry,
      (b) the maximum and minimum values of \(y\),
    4. the set of values of \(x\) for which the curve is defined.

Question 3(i)(a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Asymptote \(y=0\)B1 1 For correct equation (allow \(x\)-axis)
Question 3(i)(b):
Method 1
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y=\frac{5ax}{x^2+a^2} \Rightarrow yx^2-5ax+a^2y=0\)M1 For expressing as a quadratic in \(x\)
M1For using \(b^2-4ac\lessgtr 0\)
\(b^2\geqslant 4ac \Rightarrow 25a^2\geqslant 4a^2y^2 \Rightarrow -\frac{5}{2}\leqslant y\leqslant\frac{5}{2}\)A1 For \(25a^2-4a^2y^2\) seen or implied
A1 4For correct range
Method 2
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y=\frac{5ax}{x^2+a^2} \Rightarrow \frac{dy}{dx}=\frac{-5a(x^2-a^2)}{(x^2+a^2)^2}\)M1* For differentiating \(y\) by quotient OR product rule
\(\frac{dy}{dx}=0 \Rightarrow x=\pm a \Rightarrow y=\pm\frac{5}{2}\)A1 For correct values of \(x\)
Asymptote, sketch etc \(\Rightarrow -\frac{5}{2}\leqslant y\leqslant\frac{5}{2}\)M1 For finding \(y\) values and giving argument for range
A1(*dep) 4For correct range
Question 3(ii)(a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y=0\)B1 1 For correct equation (allow \(x\)-axis)
Question 3(ii)(b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Maximum \(\sqrt{\frac{5}{2}}\), minimum \(-\sqrt{\frac{5}{2}}\)B1\(\checkmark\) For correct maximum f.t. from (i)(b)
B1\(\checkmark\) 2For correct minimum f.t. from (i)(b); allow decimals
Question 3(ii)(c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x\geqslant 0\)B1 1 For correct set of values (allow in words)
## Question 3(i)(a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Asymptote $y=0$ | B1 **1** | For correct equation (allow $x$-axis) |

## Question 3(i)(b):

**Method 1**

| Answer/Working | Marks | Guidance |
|---|---|---|
| $y=\frac{5ax}{x^2+a^2} \Rightarrow yx^2-5ax+a^2y=0$ | M1 | For expressing as a quadratic in $x$ |
| | M1 | For using $b^2-4ac\lessgtr 0$ |
| $b^2\geqslant 4ac \Rightarrow 25a^2\geqslant 4a^2y^2 \Rightarrow -\frac{5}{2}\leqslant y\leqslant\frac{5}{2}$ | A1 | For $25a^2-4a^2y^2$ seen or implied |
| | A1 **4** | For correct range |

**Method 2**

| Answer/Working | Marks | Guidance |
|---|---|---|
| $y=\frac{5ax}{x^2+a^2} \Rightarrow \frac{dy}{dx}=\frac{-5a(x^2-a^2)}{(x^2+a^2)^2}$ | M1* | For differentiating $y$ by quotient OR product rule |
| $\frac{dy}{dx}=0 \Rightarrow x=\pm a \Rightarrow y=\pm\frac{5}{2}$ | A1 | For correct values of $x$ |
| Asymptote, sketch etc $\Rightarrow -\frac{5}{2}\leqslant y\leqslant\frac{5}{2}$ | M1 | For finding $y$ values and giving argument for range |
| | A1(*dep) **4** | For correct range |

## Question 3(ii)(a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $y=0$ | B1 **1** | For correct equation (allow $x$-axis) |

## Question 3(ii)(b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Maximum $\sqrt{\frac{5}{2}}$, minimum $-\sqrt{\frac{5}{2}}$ | B1$\checkmark$ | For correct maximum f.t. from **(i)(b)** |
| | B1$\checkmark$ **2** | For correct minimum f.t. from **(i)(b)**; allow decimals |

## Question 3(ii)(c):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $x\geqslant 0$ | B1 **1** | For correct set of values (allow in words) |

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3 The function f is defined by $\mathrm { f } ( x ) = \frac { 5 a x } { x ^ { 2 } + a ^ { 2 } }$, for $x \in \mathbb { R }$ and $a > 0$.\\
(i) For the curve with equation $y = \mathrm { f } ( x )$,
\begin{enumerate}[label=(\alph*)]
\item write down the equation of the asymptote,
\item find the range of values that $y$ can take.\\
(ii) For the curve with equation $y ^ { 2 } = \mathrm { f } ( x )$, write down\\
(a) the equation of the line of symmetry,\\
(b) the maximum and minimum values of $y$,
\item the set of values of $x$ for which the curve is defined.
\end{enumerate}

\hfill \mbox{\textit{OCR FP2 2011 Q3 [9]}}