OCR FP1 2015 June — Question 8 10 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2015
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeInfinite series convergence and sum
DifficultyChallenging +1.3 This is a standard FP1 telescoping series question with three routine parts: algebraic verification, finding a finite sum using telescoping, and evaluating an infinite series. While it requires careful bookkeeping and understanding of partial fractions in reverse, the method is well-practiced and follows a predictable pattern. Slightly above average difficulty due to the multi-step nature and being Further Maths content, but still a textbook exercise.
Spec4.06b Method of differences: telescoping series

8
  1. Show that \(\frac { 3 } { r - 1 } - \frac { 2 } { r } - \frac { 1 } { r + 1 } \equiv \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }\).
  2. Hence find an expression, in terms of \(n\), for \(\sum _ { r = 2 } ^ { n } \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }\).
  3. Hence find the value of \(\sum _ { r = 4 } ^ { \infty } \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }\).

Question 8(i):
AnswerMarks Guidance
AnswerMarks Guidance
M1Use correct common denominator, numerator must be quadratic
A1Obtain given result
[2]
Question 8(ii):
AnswerMarks Guidance
AnswerMarks Guidance
M1Express terms as differences using (i)
M1Attempt this for at least first 3 terms
A1First 3 terms all correct
A1Last 2 terms correct
\(\frac{7}{2} - \frac{3}{n} - \frac{1}{n+1}\)M1 Show terms cancelling; Need not be tidied up
A1Obtain correct answer, must be in terms of \(n\)
[6]
Question 8(iii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{5}{4}\)M1 Attempt to start summation at correct term; Could be \(\sum_2^\infty - \sum_2^3\)
A1Obtain correct answer from correct working
[2]
## Question 8(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| | M1 | Use correct common denominator, numerator must be quadratic |
| | A1 | Obtain **given** result |
| **[2]** | | |

---

## Question 8(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| | M1 | Express terms as differences using (i) |
| | M1 | Attempt this for at least first 3 terms |
| | A1 | First 3 terms all correct |
| | A1 | Last 2 terms correct |
| $\frac{7}{2} - \frac{3}{n} - \frac{1}{n+1}$ | M1 | Show terms cancelling; Need not be tidied up |
| | A1 | Obtain correct answer, must be in terms of $n$ |
| **[6]** | | |

---

## Question 8(iii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{5}{4}$ | M1 | Attempt to start summation at correct term; Could be $\sum_2^\infty - \sum_2^3$ |
| | A1 | Obtain correct answer from correct working |
| **[2]** | | |

---
8 (i) Show that $\frac { 3 } { r - 1 } - \frac { 2 } { r } - \frac { 1 } { r + 1 } \equiv \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }$.\\
(ii) Hence find an expression, in terms of $n$, for $\sum _ { r = 2 } ^ { n } \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }$.\\
(iii) Hence find the value of $\sum _ { r = 4 } ^ { \infty } \frac { 4 r + 2 } { r \left( r ^ { 2 } - 1 \right) }$.

\hfill \mbox{\textit{OCR FP1 2015 Q8 [10]}}