OCR M1 2010 January — Question 1 6 marks

Exam BoardOCR
ModuleM1 (Mechanics 1)
Year2010
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: time to ground
DifficultyModerate -0.8 This is a straightforward SUVAT application with three standard parts using given values (u=4.2, t=1.5, a=9.8). Each part requires selecting and applying one kinematic equation with no conceptual difficulty or problem-solving insight—purely mechanical substitution into standard formulas that students practice extensively.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

1 A particle \(P\) is projected vertically downwards from a fixed point \(O\) with initial speed \(4.2 \mathrm {~ms} ^ { - 1 }\), and takes 1.5 s to reach the ground. Calculate
  1. the speed of \(P\) when it reaches the ground,
  2. the height of \(O\) above the ground,
  3. the speed of \(P\) when it is 5 m above the ground.

1 A particle $P$ is projected vertically downwards from a fixed point $O$ with initial speed $4.2 \mathrm {~ms} ^ { - 1 }$, and takes 1.5 s to reach the ground. Calculate\\
(i) the speed of $P$ when it reaches the ground,\\
(ii) the height of $O$ above the ground,\\
(iii) the speed of $P$ when it is 5 m above the ground.

\hfill \mbox{\textit{OCR M1 2010 Q1 [6]}}