CAIE P1 2020 November — Question 5 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2020
SessionNovember
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeRatio of coefficients condition
DifficultyStandard +0.3 This is a straightforward binomial expansion question requiring students to find specific term coefficients, set them equal, and solve for a constant. Part (a) involves standard binomial coefficient calculation and simple algebra. Part (b) adds one extra step of multiplying by (1-x³) but remains routine. The question tests procedural fluency rather than problem-solving insight, making it slightly easier than average.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

5 In the expansion of \(\left( 2 x ^ { 2 } + \frac { a } { x } \right) ^ { 6 }\), the coefficients of \(x ^ { 6 }\) and \(x ^ { 3 }\) are equal.
  1. Find the value of the non-zero constant \(a\).
  2. Find the coefficient of \(x ^ { 6 }\) in the expansion of \(\left( 1 - x ^ { 3 } \right) \left( 2 x ^ { 2 } + \frac { a } { x } \right) ^ { 6 }\).

Question 5(a):
AnswerMarks Guidance
\(6C2 \times \left[2(x^2)\right]^4 \times \left[\frac{a}{x}\right]^2\), \(6C3 \times \left[2(x^2)\right]^3 \times \left[\frac{a}{x}\right]^3\)B1 B1 SOI Can be seen in an expansion
\(15 \times 2^4 \times a^2 = 20 \times 2^3 \times a^3\)M1 SOI Terms must be from a correct series
\(a = \frac{15 \times 2^4}{20 \times 2^3} = \frac{3}{2}\)A1 OE
Question 5(b):
AnswerMarks
\(0\)B1
## Question 5(a):

| $6C2 \times \left[2(x^2)\right]^4 \times \left[\frac{a}{x}\right]^2$, $6C3 \times \left[2(x^2)\right]^3 \times \left[\frac{a}{x}\right]^3$ | B1 B1 | SOI Can be seen in an expansion |
|---|---|---|
| $15 \times 2^4 \times a^2 = 20 \times 2^3 \times a^3$ | M1 | SOI Terms must be from a correct series |
| $a = \frac{15 \times 2^4}{20 \times 2^3} = \frac{3}{2}$ | A1 | OE |

---

## Question 5(b):

| $0$ | B1 | |
|---|---|---|

---
5 In the expansion of $\left( 2 x ^ { 2 } + \frac { a } { x } \right) ^ { 6 }$, the coefficients of $x ^ { 6 }$ and $x ^ { 3 }$ are equal.
\begin{enumerate}[label=(\alph*)]
\item Find the value of the non-zero constant $a$.
\item Find the coefficient of $x ^ { 6 }$ in the expansion of $\left( 1 - x ^ { 3 } \right) \left( 2 x ^ { 2 } + \frac { a } { x } \right) ^ { 6 }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2020 Q5 [5]}}