OCR S3 2010 January — Question 2 8 marks

Exam BoardOCR
ModuleS3 (Statistics 3)
Year2010
SessionJanuary
Marks8
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TopicLinear combinations of normal random variables
TypeSum or total of normal variables
DifficultyModerate -0.3 This is a straightforward application of standard results for sums of independent normal variables. Part (i) requires recognizing Y as the sum of 4 independent normals and standardizing. Parts (ii)-(iii) test understanding that Y and X are independent, requiring calculation of E(V) and Var(V) using linearity properties. All steps are routine for S3 level with no novel insight required, making it slightly easier than average.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

2 The amount of tomato juice, \(X \mathrm { ml }\), dispensed into cartons of a particular brand has a normal distribution with mean 504 and standard deviation 3 . The juice is sold in packs of 4 cartons, filled independently. The total amount of juice in one pack is \(Y \mathrm { ml }\).
  1. Find \(\mathrm { P } ( Y < 2000 )\). The random variable \(V\) is defined as \(Y - 4 X\).
  2. Find \(\mathrm { E } ( V )\) and \(\operatorname { Var } ( V )\).
  3. What is the probability that the amount of juice in a randomly chosen pack is more than 4 times the amount of juice in a randomly chosen carton?

2 The amount of tomato juice, $X \mathrm { ml }$, dispensed into cartons of a particular brand has a normal distribution with mean 504 and standard deviation 3 . The juice is sold in packs of 4 cartons, filled independently. The total amount of juice in one pack is $Y \mathrm { ml }$.\\
(i) Find $\mathrm { P } ( Y < 2000 )$.

The random variable $V$ is defined as $Y - 4 X$.\\
(ii) Find $\mathrm { E } ( V )$ and $\operatorname { Var } ( V )$.\\
(iii) What is the probability that the amount of juice in a randomly chosen pack is more than 4 times the amount of juice in a randomly chosen carton?

\hfill \mbox{\textit{OCR S3 2010 Q2 [8]}}