CAIE P3 2016 June — Question 6 8 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2016
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeSeparable variables
DifficultyStandard +0.3 This is a straightforward separable variables question requiring standard separation, integration of basic trigonometric functions (∫sin 2θ/(3+cos 2θ) dθ via substitution u=3+cos 2θ), and applying an initial condition. The second part requires simple analysis of the resulting expression. Slightly above average due to the trigonometric manipulation, but still a routine textbook exercise with no novel insight required.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)

6 The variables \(x\) and \(\theta\) satisfy the differential equation $$( 3 + \cos 2 \theta ) \frac { \mathrm { d } x } { \mathrm {~d} \theta } = x \sin 2 \theta$$ and it is given that \(x = 3\) when \(\theta = \frac { 1 } { 4 } \pi\).
  1. Solve the differential equation and obtain an expression for \(x\) in terms of \(\theta\).
  2. State the least value taken by \(x\).

AnswerMarks Guidance
(i) Separate variables correctly and attempt integration of at least one sideB1
Obtain term \(\ln x\)B1
Obtain term of the form \(k \ln(3 + \cos 2\theta)\), or equivalentM1
Obtain term \(-\frac{1}{2}\ln(3 + \cos 2\theta)\), or equivalentA1
Use \(x = 3, y = \frac{\pi}{3}\) to evaluate a constant or as limits in a solutionM1
with terms \(a \ln x\) and \(b \ln(3 + \cos 2\theta)\) where \(ab \neq 0\)
State correct solution in any form, e.g. \(\ln x = -\frac{1}{2}\ln(3 + \cos 2\theta) + \frac{1}{2}\ln 3\)A1
Rearrange in a correct form, e.g. \(x = \sqrt{\frac{27}{3 + \cos 2\theta}}\)A1 [7]
(ii) State answer \(x = 3\sqrt{3}/2\), or exact equivalent (accept decimal answer in [2.59, 2.60])B1 [1]
**(i)** Separate variables correctly and attempt integration of at least one side | B1 |
Obtain term $\ln x$ | B1 |
Obtain term of the form $k \ln(3 + \cos 2\theta)$, or equivalent | M1 |
Obtain term $-\frac{1}{2}\ln(3 + \cos 2\theta)$, or equivalent | A1 |
Use $x = 3, y = \frac{\pi}{3}$ to evaluate a constant or as limits in a solution | M1 |
with terms $a \ln x$ and $b \ln(3 + \cos 2\theta)$ where $ab \neq 0$ | | |
State correct solution in any form, e.g. $\ln x = -\frac{1}{2}\ln(3 + \cos 2\theta) + \frac{1}{2}\ln 3$ | A1 |
Rearrange in a correct form, e.g. $x = \sqrt{\frac{27}{3 + \cos 2\theta}}$ | A1 | [7]

**(ii)** State answer $x = 3\sqrt{3}/2$, or exact equivalent (accept decimal answer in [2.59, 2.60]) | B1 | [1]
6 The variables $x$ and $\theta$ satisfy the differential equation

$$( 3 + \cos 2 \theta ) \frac { \mathrm { d } x } { \mathrm {~d} \theta } = x \sin 2 \theta$$

and it is given that $x = 3$ when $\theta = \frac { 1 } { 4 } \pi$.\\
(i) Solve the differential equation and obtain an expression for $x$ in terms of $\theta$.\\
(ii) State the least value taken by $x$.

\hfill \mbox{\textit{CAIE P3 2016 Q6 [8]}}