CAIE P3 2016 June — Question 9 11 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2016
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeCartesian equation of a plane
DifficultyStandard +0.3 This is a standard two-part vectors question requiring routine techniques: (i) finding a plane equation via cross product of two vectors in the plane, and (ii) finding intersection of a line with a plane using parametric equations. Both parts follow textbook methods with straightforward arithmetic, making it slightly easier than average.
Spec1.10f Distance between points: using position vectors4.04a Line equations: 2D and 3D, cartesian and vector forms4.04b Plane equations: cartesian and vector forms

9 With respect to the origin \(O\), the points \(A , B , C , D\) have position vectors given by $$\overrightarrow { O A } = \mathbf { i } + 3 \mathbf { j } + 2 \mathbf { k } , \quad \overrightarrow { O B } = 2 \mathbf { i } + \mathbf { j } - \mathbf { k } , \quad \overrightarrow { O C } = 2 \mathbf { i } + 4 \mathbf { j } + \mathbf { k } , \quad \overrightarrow { O D } = - 3 \mathbf { i } + \mathbf { j } + 2 \mathbf { k }$$
  1. Find the equation of the plane containing \(A , B\) and \(C\), giving your answer in the form \(a x + b y + c z = d\).
  2. The line through \(D\) parallel to \(O A\) meets the plane with equation \(x + 2 y - z = 7\) at the point \(P\). Find the position vector of \(P\) and show that the length of \(D P\) is \(2 \sqrt { } ( 14 )\).

Question 9:
Part (i):
EITHER Method:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Obtain a vector parallel to the plane, e.g. \(\overrightarrow{AB} = \mathbf{i} - 2\mathbf{j} - 3\mathbf{k}\)B1
Use scalar product to obtain an equation in \(a\), \(b\), \(c\) e.g. \(a - 2b - 3c = 0\), \(a + b - c = 0\), or \(3b + 2c = 0\)M1
State two correct equationsA1
Solve to obtain ratio \(a:b:c\)M1
Obtain \(a:b:c = 5:-2:3\)A1
Obtain equation \(5x - 2y + 3z = 5\), or equivalentA1
OR1 Method:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Substitute for two points, e.g. \(A\) and \(B\), and obtain \(a + 3b + 2c = d\) and \(2a + b - c = d\)(B1)
Substitute for another point, e.g. \(C\), to obtain a third equation and eliminate one unknown entirely from all three equationsM1
Obtain two correct equations in three unknowns, e.g. in \(a\), \(b\), \(c\)A1
Solve to obtain their ratioM1
Obtain \(a:b:c = 5:-2:3\), \(a:c:d = 5:3:5\), \(a:b:d = 5:-2:5\), or \(b:c:d = -2:3:5\)A1
Obtain equation \(5x - 2y + 3z = 5\), or equivalentA1)
OR2 Method:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Obtain a vector parallel to the plane, e.g. \(\overrightarrow{AC} = \mathbf{i} + \mathbf{j} - \mathbf{k}\)(B1)
Obtain a second such vector and calculate their vector product, e.g. \((\mathbf{i} - 2\mathbf{j} - 3\mathbf{k}) \times (\mathbf{i} + \mathbf{j} - \mathbf{k})\)M1
Obtain two correct components of the productA1
Obtain correct answer e.g. \(5\mathbf{i} - 2\mathbf{j} + 3\mathbf{k}\)A1
Substitute in \(5x - 2y + 3z = d\) to find \(d\)M1
Obtain equation \(5x - 2y + 3z = 5\), or equivalentA1)
OR3 Method:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Obtain a vector parallel to the plane, e.g. \(\overrightarrow{BC} = 3\mathbf{j} + 2\mathbf{k}\)(B1)
Obtain a second such vector and form correctly a 2-parameter equation for the planeM1
Obtain a correct equation, e.g. \(\mathbf{r} = \mathbf{i} + 3\mathbf{j} + 2\mathbf{k} + \lambda(\mathbf{i} - 2\mathbf{j} - 3\mathbf{k}) + \mu(3\mathbf{j} + 2\mathbf{k})\)A1
State three correct equations in \(x\), \(y\), \(z\), \(\lambda\), \(\mu\)A1
Eliminate \(\lambda\) and \(\mu\)M1
Obtain equation \(3x - 2y + 3z = 5\), or equivalentA1) [6]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Correctly form an equation for the line through \(D\) parallel to \(OA\)M1
Obtain a correct equation e.g. \(\mathbf{r} = -3\mathbf{i} + \mathbf{j} + 2\mathbf{k} + \lambda(\mathbf{i} + 3\mathbf{j} + 2\mathbf{k})\)A1
Substitute components in the equation of the plane and solve for \(\lambda\)M1
Obtain \(\lambda = 2\) and position vector \(-\mathbf{i} + 7\mathbf{j} + 6\mathbf{k}\) for \(P\)A1
Obtain the given answer correctlyA1 [5]
# Question 9:

## Part (i):

**EITHER Method:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Obtain a vector parallel to the plane, e.g. $\overrightarrow{AB} = \mathbf{i} - 2\mathbf{j} - 3\mathbf{k}$ | B1 | |
| Use scalar product to obtain an equation in $a$, $b$, $c$ e.g. $a - 2b - 3c = 0$, $a + b - c = 0$, or $3b + 2c = 0$ | M1 | |
| State two correct equations | A1 | |
| Solve to obtain ratio $a:b:c$ | M1 | |
| Obtain $a:b:c = 5:-2:3$ | A1 | |
| Obtain equation $5x - 2y + 3z = 5$, or equivalent | A1 | |

**OR1 Method:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Substitute for two points, e.g. $A$ and $B$, and obtain $a + 3b + 2c = d$ and $2a + b - c = d$ | (B1) | |
| Substitute for another point, e.g. $C$, to obtain a third equation and eliminate one unknown entirely from all three equations | M1 | |
| Obtain two correct equations in three unknowns, e.g. in $a$, $b$, $c$ | A1 | |
| Solve to obtain their ratio | M1 | |
| Obtain $a:b:c = 5:-2:3$, $a:c:d = 5:3:5$, $a:b:d = 5:-2:5$, or $b:c:d = -2:3:5$ | A1 | |
| Obtain equation $5x - 2y + 3z = 5$, or equivalent | A1) | |

**OR2 Method:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Obtain a vector parallel to the plane, e.g. $\overrightarrow{AC} = \mathbf{i} + \mathbf{j} - \mathbf{k}$ | (B1) | |
| Obtain a second such vector and calculate their vector product, e.g. $(\mathbf{i} - 2\mathbf{j} - 3\mathbf{k}) \times (\mathbf{i} + \mathbf{j} - \mathbf{k})$ | M1 | |
| Obtain two correct components of the product | A1 | |
| Obtain correct answer e.g. $5\mathbf{i} - 2\mathbf{j} + 3\mathbf{k}$ | A1 | |
| Substitute in $5x - 2y + 3z = d$ to find $d$ | M1 | |
| Obtain equation $5x - 2y + 3z = 5$, or equivalent | A1) | |

**OR3 Method:**

| Answer/Working | Mark | Guidance |
|---|---|---|
| Obtain a vector parallel to the plane, e.g. $\overrightarrow{BC} = 3\mathbf{j} + 2\mathbf{k}$ | (B1) | |
| Obtain a second such vector and form correctly a 2-parameter equation for the plane | M1 | |
| Obtain a correct equation, e.g. $\mathbf{r} = \mathbf{i} + 3\mathbf{j} + 2\mathbf{k} + \lambda(\mathbf{i} - 2\mathbf{j} - 3\mathbf{k}) + \mu(3\mathbf{j} + 2\mathbf{k})$ | A1 | |
| State three correct equations in $x$, $y$, $z$, $\lambda$, $\mu$ | A1 | |
| Eliminate $\lambda$ and $\mu$ | M1 | |
| Obtain equation $3x - 2y + 3z = 5$, or equivalent | A1) | [6] |

## Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Correctly form an equation for the line through $D$ parallel to $OA$ | M1 | |
| Obtain a correct equation e.g. $\mathbf{r} = -3\mathbf{i} + \mathbf{j} + 2\mathbf{k} + \lambda(\mathbf{i} + 3\mathbf{j} + 2\mathbf{k})$ | A1 | |
| Substitute components in the equation of the plane and solve for $\lambda$ | M1 | |
| Obtain $\lambda = 2$ and position vector $-\mathbf{i} + 7\mathbf{j} + 6\mathbf{k}$ for $P$ | A1 | |
| Obtain the given answer correctly | A1 | [5] |

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9 With respect to the origin $O$, the points $A , B , C , D$ have position vectors given by

$$\overrightarrow { O A } = \mathbf { i } + 3 \mathbf { j } + 2 \mathbf { k } , \quad \overrightarrow { O B } = 2 \mathbf { i } + \mathbf { j } - \mathbf { k } , \quad \overrightarrow { O C } = 2 \mathbf { i } + 4 \mathbf { j } + \mathbf { k } , \quad \overrightarrow { O D } = - 3 \mathbf { i } + \mathbf { j } + 2 \mathbf { k }$$

(i) Find the equation of the plane containing $A , B$ and $C$, giving your answer in the form $a x + b y + c z = d$.\\
(ii) The line through $D$ parallel to $O A$ meets the plane with equation $x + 2 y - z = 7$ at the point $P$. Find the position vector of $P$ and show that the length of $D P$ is $2 \sqrt { } ( 14 )$.

\hfill \mbox{\textit{CAIE P3 2016 Q9 [11]}}