OCR S1 2011 June — Question 3 10 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2011
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeSum or combination of independent binomial values
DifficultyModerate -0.3 Part (i) involves straightforward binomial probability calculations using the formula or tables, and variance recall. Part (ii) requires recognizing that the sum of two independent B(2,1/4) variables follows B(4,1/4), then calculating P(sum=1), which is a standard application but requires slightly more thought than pure recall. Overall, this is slightly easier than average due to being mostly routine calculations with minimal problem-solving.
Spec5.02b Expectation and variance: discrete random variables5.02c Linear coding: effects on mean and variance

3
  1. A random variable, \(X\), has the distribution \(\mathrm { B } ( 12,0.85 )\). Find
    1. \(\mathrm { P } ( X > 10 )\),
    2. \(\mathrm { P } ( X = 10 )\),
    3. \(\operatorname { Var } ( X )\).
    4. A random variable, \(Y\), has the distribution \(\mathrm { B } \left( 2 , \frac { 1 } { 4 } \right)\). Two independent values of \(Y\) are found. Find the probability that the sum of these two values is 1 .

3 (i) A random variable, $X$, has the distribution $\mathrm { B } ( 12,0.85 )$. Find
\begin{enumerate}[label=(\alph*)]
\item $\mathrm { P } ( X > 10 )$,
\item $\mathrm { P } ( X = 10 )$,
\item $\operatorname { Var } ( X )$.\\
(ii) A random variable, $Y$, has the distribution $\mathrm { B } \left( 2 , \frac { 1 } { 4 } \right)$. Two independent values of $Y$ are found. Find the probability that the sum of these two values is 1 .
\end{enumerate}

\hfill \mbox{\textit{OCR S1 2011 Q3 [10]}}