OCR S1 2011 June — Question 2 5 marks

Exam BoardOCR
ModuleS1 (Statistics 1)
Year2011
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of Spearman’s rank correlation coefficien
TypeCalculate Spearman's coefficient only
DifficultyEasy -1.2 This is a straightforward calculation of Spearman's coefficient with only 4 data points and no ties, requiring simple arithmetic of differences squared and substitution into the formula. It's below average difficulty as it's purely mechanical with minimal computation.
Spec5.08e Spearman rank correlation

2 The orders in which 4 contestants, \(P , Q , R\) and \(S\), were placed in two competitions are shown in the table.
Position1st2nd3rd4th
Competition 1\(Q\)\(R\)\(S\)\(P\)
Competition 2\(Q\)\(P\)\(R\)\(S\)
Calculate Spearman's rank correlation coefficient between these two orders.

AnswerMarks Guidance
Answer: Attempt ranks 4 1 2 3 or 1 2 3 4 or 1 2 3 4 or 2 1 3 4; \(\Sigma d^2\) attempted (or 6); \(1 - \frac{6\Sigma d^2}{4(4^2-1)} = \frac{2}{5}\)M1, A1, M1, M1, A1 Ignore labels of rows or columns; No ranks seen, \(d = (0), \pm1, \pm1, \pm2\), or \(d^2 = (0), 1, 1, 4\) any order: M1A1M1; NOT \((\Sigma d)^2\); No wking, \(\Sigma d^2 = 6\): M1A1M1; No wking, ans \(\frac{2}{5}\): Full mks; Allow both sets of ranks reversed; NB incorrect method: 2 3 4 1 or 2 1 3 4 OR \(d = (0), \pm2, \pm1, \pm3\) any order OR \(d^2 = (0), 4, 1, 9\) any order (leading to \(\Sigma d^2 = 14\) and \(r_s = -\frac{2}{5}\)): M0A0M1M1A0
Question 3ia
AnswerMarks Guidance
Answer: \((1 - 0.5565) \text{ or } 12 \times 0.85^{11} \times (1-0.85) + 0.85^{12}\) or \(1 - (1-0.85)^{12} - \ldots ^{12}C_{10} \times 0.85^{10}(1-0.85)^2\) ie 1 – (all 11 correct binomial terms)M1, A1, 2 or \(1 - 0.557\); NB \(1 - 0.4435\) (oe): M0A0
Question 3ib
AnswerMarks Guidance
Answer: \(0.5565 - 0.2642\) or \(^{12}C_{10}(1-0.85)^7(0.85)^{10}\)M1, 2, A1, 2 or \(0.557 - 0.264\)
Question 3ic
AnswerMarks
Answer: \(12 \times 0.85 \times (1-0.85)\)M1
Question 3ii
AnswerMarks Guidance
Answer: \(1.53\)A1 \((\frac{3}{4})^2\) AND \(\frac{3}{4} \times \frac{1}{4}\) seen (possibly × 2); eg \((\frac{3}{4})^2 + \frac{3}{4} \times \frac{1}{4}\) or \(2 \times (\frac{3}{4})^2 + 2 \times \frac{3}{4} \times \frac{1}{4}\) or \(0.5625 + 0.1875\) or \(0.5625 + 0.375\); or eg \(\frac{9}{16}\) and \(\frac{3}{16}\) or \(\frac{9}{16}\) and \(\frac{3}{8}\) eg in table or list; or \((\frac{3}{4})^2 \times 2 \times \frac{3}{4} \times \frac{1}{4}\) oe or \(\frac{27}{128}\) or \(0.211\); Fully correct method; \(= \frac{27}{64}\) or \(0.422\) (3 sfs)
Question 4i
AnswerMarks Guidance
Answer: Method is either: Just \(4 \div 3\) or \(\frac{4}{3}\) or: Use of ratio of correct frequencies AND ratio of widths (correct or 4 and 2)M1, M1 Correct calc'n using 5.6, 28, 4, 5, 3 oe: M2; Correct calc'n using 5.6, 28, 4, 4, 2 oe: M1; ie fully correct method: M2; or: incorrect class widths, otherwise correct method: M1
Question 4ii
AnswerMarks Guidance
Answer: \(5.6 \times \frac{4}{28} \times \frac{5}{3}\) or \(0.8 \times \frac{5}{3}\) or \((5.6 \div \frac{28}{5}) \times \frac{4}{3}\) or \(\frac{4}{3} \div 3\) oeM2, M1, M1, M1 \(\frac{4}{3}\) correctly obtained (or no wking) then further incorrect: M1M0A0; Use of ratio of widths OR freqs but not both: M0 eg \(5.6 \times \frac{4}{28}(= 0.8)\) or \(5.6 \times \frac{5}{3}(= 3.36)\): M0
Question 4iii
AnswerMarks Guidance
Answer: \(= 1\frac{1}{3}\) or \(\frac{4}{3}\) or \(1.33\) (3 sf) oeA1 \(\frac{4}{3} = 2\): M0M0A0
Question 4ii (median)
AnswerMarks Guidance
Answer: 25 or 26 or 25.5; Med is 21st (or 22nd or 21.5th) in 31-35 class or "≈25 – 4"; Can be implied by calc'n; Med > 33 or "more than"B1, B1, B1 or 25 & 26; or med in last ≈ 7 in class or 33 ≈ 18th in class or 33 ≈ 18th in whole set; Can be implied by diagram; indep; The "≈" sign means ± 2; Allow on boundaries. Not class widths; Calc'ns need not be correct but need to contain relevant figures for gaining B1B1; Alternative Method: 33 ≈ 18th value B1; More values above 33 than below oe B1; Med > 33 B1; Ignore comment on skew; NB Use EITHER the main method OR the Alternative Method (above), not a mixture of the two. Choose the method that gives most marks.
Question 4iii
AnswerMarks Guidance
Answer: > 3 mid-pts attempted; \(\Sigma fx \div 50\) attempted \((= \frac{1819}{50})\); \(= 36.38\) or \(36.4\) (3 sf); \(\Sigma fx^2\) attempted \((= 68055.5)\); \(\sqrt{\frac{68055.5}{50} - (\frac{1819}{50})^2}\) or \(\sqrt{1361.11 - 36.38^2}\) \((= \sqrt{37.6056})\); \(= 6.13\) (3 sfs)M1, M1, A1, M1, M1, A1 seen or implied; > 3 terms. or 36 with correct working; Allow on boundaries. Not class widths; > 3 terms. Allow on boundaries. Not class widths (3364, 30492, 22963.5, 11236); completely correct method except midpts & ft their mean, dep not \(\sqrt{\text{neg}}\) Allow class widths for this mark only; NB mark is not just for "−mean"−, unlike q5(iii); \(\Sigma(fx)^2\): M0M0A0; If no wking for \(\Sigma fx^2\), check using their \(x\) and \(f\); If no wking or unclear wking: full mks for each correct ans for incorrect ans: 35.8 ≤ \(\mu\) ≤ 36.9 M0M1A0; 6.0 ≤ \(sd\) ≤ 6.25 M1M0A0; Alt for variance: \(\Sigma f(x - \bar{x})^2\) (= 1880.28); \(\sqrt{\frac{1880.28}{50}}\); \(= 6.13\) (3 sf)
Question 4iv
AnswerMarks Guidance
Answer: (a) Decrease (b) Increase (c) Same (d) SameB1B1, B1B1, 4 Ignore other, eg "slightly" or "probably"
Question 5 (if done with replacement)
No marks in any part of this question.
Question 5i
AnswerMarks Guidance
Answer: All correct probs correctly placed, matching labels, if anyB2, 2 B1 for 4 correct probs anywhere; Allow B2 with missing labels but only if probs consistently placed, ie R above B throughout
Question 5ii
AnswerMarks Guidance
Answer: \(\frac{4}{10} \times \frac{9}{10} + \frac{6}{10} \times \frac{9}{10} + \frac{8}{10} \times \frac{9}{10} + \frac{10}{10} \times \frac{9}{10}\) or \(\frac{4}{15} + \frac{6}{15} + \frac{6}{6}\) \((= \frac{3}{5}\) (AG)B2, 2, B2, 2 B1: two of these products (or their results) added (not multiplied); or \(1 - (\frac{6}{10} \times \frac{9}{10} + \frac{8}{10} \times \frac{9}{10} + \frac{10}{10} \times \frac{9}{10})\) or \(1 - (\frac{1}{6} + \frac{10}{15})\)
Question 6ia
AnswerMarks Guidance
Answer: 5040 or 6! or 5!×6 or 720B1, 1, M1 NOT 6! in denom
Question 6ib
AnswerMarks Guidance
Answer: \(\div 7!\) or ÷ "5040" or 1440 or \((5! \text{ or } 6!) \times 2\); \(= \frac{3}{7}\) oe or \(0.286\) (3 sf)M1, M1, A1 Any ÷ 7! or "5040" but NOT any × 2; eg \(\frac{6!}{5040}\) or \(\frac{1}{7}\) or \(0.143\) or \(\frac{1}{21}\) (3 sfs): M1M1A0
Question 6iia
AnswerMarks Guidance
Answer: 3! × 4! alone or 144M1 \(\frac{4}{7} \times \frac{3}{6} \times \frac{2}{5} \times \frac{1}{4} \times \frac{3!}{4}\) oe or \(7C3 \text{ or } 7C4\)
Question 6iib
AnswerMarks Guidance
Answer: \((÷ 7!\) or "5040") \(= \frac{1}{35}\) oe or \(0.0286\) (3sf)A1, 2 Not \(3! \times 4! \times \ldots\) (eg not \(3! \times 4! \times 5\)); not \(\frac{3!×4!}{...}\) ; not \(\frac{31×4!}{...}\)
Question 6b
AnswerMarks Guidance
Answer: 5 seen or 5! seen; 3! × 4! × 5 or 5! × 3! or 720 or 5 × 144M1, M1 or GGGBBBB, BGGGGBB, BRGGGBB, BBRGGGB, BBBRGG GBB or continuing pattern; or \(5 \times \frac{3!}{7} \times \frac{4!}{6}\) oe; \(= \frac{1}{7}\) oe or \(0.143\) (3 sf)
Question 7i
AnswerMarks Guidance
Answer: \(x\)B1, 1 Ignore explanations. "Neither" or "Both": B0
Question 7ii
AnswerMarks Guidance
Answer: Diag showing vertical differences onlyB1 Allow description instead of diag: "Distances from pts to line // to y-axis" oe; Allow ≥ one line, from a point to the line; State that sum of squares of these is min oe
Question 7iii
AnswerMarks Guidance
Answer: –1; Ranks opposite or reversed or perfect neg corr'n between ranks oeB1, B1dep 2 Not approx –1; As \(x\) increases, \(y\) decreases
Question 7iv
AnswerMarks Guidance
Answer: "Negative" or "Not –1"B1, 1 eg "Strong neg" or any negative value > –1 or "Close to –1"
**Answer:** Attempt ranks 4 1 2 3 or 1 2 3 4 or 1 2 3 4 or 2 1 3 4; $\Sigma d^2$ attempted (or 6); $1 - \frac{6\Sigma d^2}{4(4^2-1)} = \frac{2}{5}$ | **M1, A1, M1, M1, A1** | Ignore labels of rows or columns; No ranks seen, $d = (0), \pm1, \pm1, \pm2$, or $d^2 = (0), 1, 1, 4$ any order: M1A1M1; NOT $(\Sigma d)^2$; No wking, $\Sigma d^2 = 6$: M1A1M1; No wking, ans $\frac{2}{5}$: Full mks; Allow both sets of ranks reversed; NB incorrect method: 2 3 4 1 or 2 1 3 4 OR $d = (0), \pm2, \pm1, \pm3$ any order OR $d^2 = (0), 4, 1, 9$ any order (leading to $\Sigma d^2 = 14$ and $r_s = -\frac{2}{5}$): M0A0M1M1A0

## Question 3ia

**Answer:** $(1 - 0.5565) \text{ or } 12 \times 0.85^{11} \times (1-0.85) + 0.85^{12}$ or $1 - (1-0.85)^{12} - \ldots ^{12}C_{10} \times 0.85^{10}(1-0.85)^2$ ie 1 – (all 11 correct binomial terms) | **M1, A1, 2** | or $1 - 0.557$; NB $1 - 0.4435$ (oe): M0A0

## Question 3ib

**Answer:** $0.5565 - 0.2642$ or $^{12}C_{10}(1-0.85)^7(0.85)^{10}$ | **M1, 2, A1, 2** | or $0.557 - 0.264$

## Question 3ic

**Answer:** $12 \times 0.85 \times (1-0.85)$ | **M1** |

## Question 3ii

**Answer:** $1.53$ | **A1** | $(\frac{3}{4})^2$ AND $\frac{3}{4} \times \frac{1}{4}$ seen (possibly × 2); eg $(\frac{3}{4})^2 + \frac{3}{4} \times \frac{1}{4}$ or $2 \times (\frac{3}{4})^2 + 2 \times \frac{3}{4} \times \frac{1}{4}$ or $0.5625 + 0.1875$ or $0.5625 + 0.375$; or eg $\frac{9}{16}$ and $\frac{3}{16}$ or $\frac{9}{16}$ and $\frac{3}{8}$ eg in table or list; or $(\frac{3}{4})^2 \times 2 \times \frac{3}{4} \times \frac{1}{4}$ oe or $\frac{27}{128}$ or $0.211$; Fully correct method; $= \frac{27}{64}$ or $0.422$ (3 sfs) | **M1, M1, M1, A1** | Allow even if further incorrect wking; Ans 0.211: check wking but probably gets M1M1M0A0; Use of 0.85 instead of $\frac{1}{4}$: MR max M1M1M1A0

## Question 4i

**Answer:** Method is either: Just $4 \div 3$ or $\frac{4}{3}$ or: Use of ratio of correct frequencies AND ratio of widths (correct or 4 and 2) | **M1, M1** | Correct calc'n using 5.6, 28, 4, 5, 3 oe: M2; Correct calc'n using 5.6, 28, 4, 4, 2 oe: M1; ie fully correct method: M2; or: incorrect class widths, otherwise correct method: M1

## Question 4ii

**Answer:** $5.6 \times \frac{4}{28} \times \frac{5}{3}$ or $0.8 \times \frac{5}{3}$ or $(5.6 \div \frac{28}{5}) \times \frac{4}{3}$ or $\frac{4}{3} \div 3$ oe | **M2, M1, M1, M1** | $\frac{4}{3}$ correctly obtained (or no wking) then further incorrect: M1M0A0; Use of ratio of widths OR freqs but not both: M0 eg $5.6 \times \frac{4}{28}(= 0.8)$ or $5.6 \times \frac{5}{3}(= 3.36)$: M0

## Question 4iii

**Answer:** $= 1\frac{1}{3}$ or $\frac{4}{3}$ or $1.33$ (3 sf) oe | **A1** | $\frac{4}{3} = 2$: M0M0A0

## Question 4ii (median)

**Answer:** 25 or 26 or 25.5; Med is 21st (or 22nd or 21.5th) in 31-35 class or "≈25 – 4"; Can be implied by calc'n; Med > 33 or "more than" | **B1, B1, B1** | or 25 & 26; or med in last ≈ 7 in class or 33 ≈ 18th in class or 33 ≈ 18th in whole set; Can be implied by diagram; indep; The "≈" sign means ± 2; Allow on boundaries. Not class widths; Calc'ns need not be correct but need to contain relevant figures for gaining B1B1; **Alternative Method:** 33 ≈ 18th value B1; More values above 33 than below oe B1; Med > 33 B1; Ignore comment on skew; NB Use EITHER the main method OR the Alternative Method (above), not a mixture of the two. Choose the method that gives most marks.

## Question 4iii

**Answer:** > 3 mid-pts attempted; $\Sigma fx \div 50$ attempted $(= \frac{1819}{50})$; $= 36.38$ or $36.4$ (3 sf); $\Sigma fx^2$ attempted $(= 68055.5)$; $\sqrt{\frac{68055.5}{50} - (\frac{1819}{50})^2}$ or $\sqrt{1361.11 - 36.38^2}$ $(= \sqrt{37.6056})$; $= 6.13$ (3 sfs) | **M1, M1, A1, M1, M1, A1** | seen or implied; > 3 terms. or 36 with correct working; Allow on boundaries. Not class widths; > 3 terms. Allow on boundaries. Not class widths (3364, 30492, 22963.5, 11236); completely correct method except midpts & ft their mean, dep not $\sqrt{\text{neg}}$ Allow class widths for this mark only; NB mark is not just for "−mean"−, unlike q5(iii); $\Sigma(fx)^2$: M0M0A0; If no wking for $\Sigma fx^2$, check using their $x$ and $f$; If no wking or unclear wking: full mks for each correct ans for incorrect ans: 35.8 ≤ $\mu$ ≤ 36.9 M0M1A0; 6.0 ≤ $sd$ ≤ 6.25 M1M0A0; **Alt for variance:** $\Sigma f(x - \bar{x})^2$ (= 1880.28); $\sqrt{\frac{1880.28}{50}}$; $= 6.13$ (3 sf) | M1, M1, A1

## Question 4iv

**Answer:** (a) Decrease (b) Increase (c) Same (d) Same | **B1B1, B1B1, 4** | Ignore other, eg "slightly" or "probably"

## Question 5 (if done with replacement)

No marks in any part of this question.

## Question 5i

**Answer:** All correct probs correctly placed, matching labels, if any | **B2, 2** | B1 for 4 correct probs anywhere; Allow B2 with missing labels but only if probs consistently placed, ie R above B throughout

## Question 5ii

**Answer:** $\frac{4}{10} \times \frac{9}{10} + \frac{6}{10} \times \frac{9}{10} + \frac{8}{10} \times \frac{9}{10} + \frac{10}{10} \times \frac{9}{10}$ or $\frac{4}{15} + \frac{6}{15} + \frac{6}{6}$ $(= \frac{3}{5}$ (AG) | **B2, 2, B2, 2** | B1: two of these products (or their results) added (not multiplied); or $1 - (\frac{6}{10} \times \frac{9}{10} + \frac{8}{10} \times \frac{9}{10} + \frac{10}{10} \times \frac{9}{10})$ or $1 - (\frac{1}{6} + \frac{10}{15})$ | B1: 1 – two of these products (or results) added (not multiplied); NB incorrect methods can lead to correct ans; AG so no wking no mks; No ft from tree in (i)

## Question 6ia

**Answer:** 5040 or 6! or 5!×6 or 720 | **B1, 1, M1** | NOT 6! in denom

## Question 6ib

**Answer:** $\div 7!$ or ÷ "5040" or 1440 or $(5! \text{ or } 6!) \times 2$; $= \frac{3}{7}$ oe or $0.286$ (3 sf) | **M1, M1, A1** | Any ÷ 7! or "5040" but NOT any × 2; eg $\frac{6!}{5040}$ or $\frac{1}{7}$ or $0.143$ or $\frac{1}{21}$ (3 sfs): M1M1A0

## Question 6iia

**Answer:** 3! × 4! alone or 144 | **M1** | $\frac{4}{7} \times \frac{3}{6} \times \frac{2}{5} \times \frac{1}{4} \times \frac{3!}{4}$ oe or $7C3 \text{ or } 7C4$

## Question 6iib

**Answer:** $(÷ 7!$ or "5040") $= \frac{1}{35}$ oe or $0.0286$ (3sf) | **A1, 2** | Not $3! \times 4! \times \ldots$ (eg not $3! \times 4! \times 5$); not $\frac{3!×4!}{...}$ ; not $\frac{31×4!}{...}$

## Question 6b

**Answer:** 5 seen or 5! seen; 3! × 4! × 5 or 5! × 3! or 720 or 5 × 144 | **M1, M1** | or GGGBBBB, BGGGGBB, BRGGGBB, BBRGGGB, BBBRGG GBB or continuing pattern; or $5 \times \frac{3!}{7} \times \frac{4!}{6}$ oe; $= \frac{1}{7}$ oe or $0.143$ (3 sf) | **A1, 3** | NB no mark for ÷ 7! or "5040" in this part

## Question 7i

**Answer:** $x$ | **B1, 1** | Ignore explanations. "Neither" or "Both": B0

## Question 7ii

**Answer:** Diag showing vertical differences only | **B1** | Allow description instead of diag: "Distances from pts to line // to y-axis" oe; Allow ≥ one line, from a point to the line; State that sum of squares of these is min oe | **B1, 2** | dep vert or horiz lines (not both) drawn or described

## Question 7iii

**Answer:** –1; Ranks opposite or reversed or perfect neg corr'n between ranks oe | **B1, B1dep 2** | Not approx –1; As $x$ increases, $y$ decreases | B1 | Allow eg: –1 because neg corr'n so ranks must be reversed; Ignore other; NOT neg corr'n or strong neg rel'nship oe; NOT comment about "disagreement" or "agreement"

## Question 7iv

**Answer:** "Negative" or "Not –1" | **B1, 1** | eg "Strong neg" or any negative value > –1 or "Close to –1"
2 The orders in which 4 contestants, $P , Q , R$ and $S$, were placed in two competitions are shown in the table.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | }
\hline
Position & 1st & 2nd & 3rd & 4th \\
\hline
Competition 1 & $Q$ & $R$ & $S$ & $P$ \\
\hline
Competition 2 & $Q$ & $P$ & $R$ & $S$ \\
\hline
\end{tabular}
\end{center}

Calculate Spearman's rank correlation coefficient between these two orders.

\hfill \mbox{\textit{OCR S1 2011 Q2 [5]}}