5 The stem-and-leaf diagram shows the masses, in grams, of 23 plums, measured correct to the nearest gram.
| 5 | 5 | 6 | 7 | 8 | 8 | 9 | | |
| 6 | 1 | 2 | 3 | 5 | 6 | 8 | 9 | |
| 7 | 0 | 0 | 2 | 4 | 5 | 6 | 7 | 8 |
| 8 | 0 | | | | | | | |
| 9 | 7 | | | | | | | |
| 9 | | | | | | | | |
\(\quad\) Key \(: 6 \mid 2\) means 62
- Find the median and interquartile range of these masses.
- State one advantage of using the interquartile range rather than the standard deviation as a measure of the variation in these masses.
- State one advantage and one disadvantage of using a stem-and-leaf diagram rather than a box-and-whisker plot to represent data.
- James wished to calculate the mean and standard deviation of the given data. He first subtracted 5 from each of the digits to the left of the line in the stem-and-leaf diagram, giving the following.
| 0 | 5 | 6 | 7 | 8 | 8 | 9 | | | |
| 1 | 1 | 2 | 3 | 5 | 6 | 8 | 9 | | |
| 2 | 0 | 0 | 2 | 4 | 5 | 6 | 7 | 8 | |
| 3 | 0 | | | | | | | | |
| 4 | 7 | | | | | | | | |
The mean and standard deviation of the data in this diagram are 18.1 and 9.7 respectively, correct to 1 decimal place. Write down the mean and standard deviation of the data in the original diagram.