OCR C4 2013 January — Question 4 8 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2013
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors 3D & Lines
TypeShow lines intersect and find intersection point
DifficultyStandard +0.3 This is a standard two-part vector line question requiring systematic equation solving to find intersection (equating components and checking consistency) and then applying the scalar product formula for angle between direction vectors. While it involves multiple steps and careful algebraic manipulation, it follows a well-practiced procedure with no novel insight required, making it slightly easier than average.
Spec4.04c Scalar product: calculate and use for angles4.04e Line intersections: parallel, skew, or intersecting

4 The equations of two lines are $$\mathbf { r } = \mathbf { i } + 2 \mathbf { j } + \lambda ( 2 \mathbf { i } + \mathbf { j } + 3 \mathbf { k } ) \text { and } \mathbf { r } = 6 \mathbf { i } + 8 \mathbf { j } + \mathbf { k } + \mu ( \mathbf { i } + 4 \mathbf { j } - 5 \mathbf { k } ) .$$
  1. Show that these lines meet, and find the coordinates of the point of intersection.
  2. Find the acute angle between these lines.

Question 4(i):
AnswerMarks Guidance
AnswerMarks Guidance
Produce (at least 2) relevant equationsM1 e.g. \(1+2\lambda = 6+\mu\), \(2+\lambda = 8+4\mu\), \(3\lambda = 1-5\mu\)
Eliminate either \(\lambda\) or \(\mu\) from 2 of them and solve for the otherM1 soi by correct \((\lambda, \mu)\)
\(\lambda = 2\) and \(\mu = -1\) caoA1 or e.g. \(\lambda = 2\) from 2 different pairs
Check that \((\lambda, \mu) = (2, -1)\) satisfies all equationsB1 This must be convincing; check unusual arguments; dep previous M1M1A1 earned
\(P\) is \((5, 4, 6)\) caoA1 Allow any reasonable vector notation
[5]
Question 4(ii):
AnswerMarks Guidance
AnswerMarks Guidance
Using \(\begin{pmatrix}2\\1\\3\end{pmatrix}\) and \(\begin{pmatrix}1\\4\\-5\end{pmatrix}\)M1 i.e. correct parts for direction vectors
Using \(\cos\theta = \frac{\mathbf{a.b}}{\mathbf{a}
\(68.2°\ldots\) (not \(111.8\ldots\))A1 or \(1.19\) radians
[3]
# Question 4(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Produce (at least 2) relevant equations | M1 | e.g. $1+2\lambda = 6+\mu$, $2+\lambda = 8+4\mu$, $3\lambda = 1-5\mu$ |
| Eliminate either $\lambda$ or $\mu$ from 2 of them and solve for the other | M1 | soi by correct $(\lambda, \mu)$ |
| $\lambda = 2$ and $\mu = -1$ cao | A1 | or e.g. $\lambda = 2$ from 2 different pairs |
| Check that $(\lambda, \mu) = (2, -1)$ satisfies all equations | B1 | This must be convincing; check unusual arguments; dep previous M1M1A1 earned |
| $P$ is $(5, 4, 6)$ cao | A1 | Allow any reasonable vector notation |
| **[5]** | | |

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# Question 4(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Using $\begin{pmatrix}2\\1\\3\end{pmatrix}$ and $\begin{pmatrix}1\\4\\-5\end{pmatrix}$ | M1 | i.e. correct parts for direction vectors |
| Using $\cos\theta = \frac{\mathbf{a.b}}{|\mathbf{a}||\mathbf{b}|}$ giving value $\frac{n}{\sqrt{a}\sqrt{b}}$ | M1 | For any 2 meaningful vectors; expect $\frac{-9}{\sqrt{14}\sqrt{42}}$ |
| $68.2°\ldots$ (not $111.8\ldots$) | A1 | or $1.19$ radians |
| **[3]** | | |

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4 The equations of two lines are

$$\mathbf { r } = \mathbf { i } + 2 \mathbf { j } + \lambda ( 2 \mathbf { i } + \mathbf { j } + 3 \mathbf { k } ) \text { and } \mathbf { r } = 6 \mathbf { i } + 8 \mathbf { j } + \mathbf { k } + \mu ( \mathbf { i } + 4 \mathbf { j } - 5 \mathbf { k } ) .$$

(i) Show that these lines meet, and find the coordinates of the point of intersection.\\
(ii) Find the acute angle between these lines.

\hfill \mbox{\textit{OCR C4 2013 Q4 [8]}}