OCR MEI C1 2014 June — Question 5 4 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2014
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeSolve linear inequality
DifficultyEasy -1.8 This is a straightforward algebraic rearrangement requiring only expansion of brackets and collecting terms with 'a' on one side. It's simpler than typical A-level questions as it involves only basic manipulation with no problem-solving element, making it easier than average even for C1.
Spec1.02c Simultaneous equations: two variables by elimination and substitution

5 Make \(a\) the subject of \(3 ( a + 4 ) = a c + 5 f\).

Question 5:
AnswerMarks Guidance
AnswerMarks Guidance
\(3a + 12\ [= ac + 5f]\)M1 For expanding brackets correctly; annotate this question if partially correct
\(3a - ac = 5f - 12\) or ftM1 For collecting \(a\) terms on one side, remaining terms on other; ft only if two \(a\) terms
\(a(3-c) = 5f - 12\) or ftM1 For factorising \(a\) terms; may be implied by final answer; ft only if two \(a\) terms, needing factorising; may be earned before 2nd M1
\(\left[a =\right] \dfrac{5f-12}{3-c}\) oe or ft as final answerM1 For division by their two-term factor; for all 4 marks to be earned, work must be fully correct
[4]
## Question 5:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $3a + 12\ [= ac + 5f]$ | M1 | For expanding brackets correctly; annotate this question if partially correct |
| $3a - ac = 5f - 12$ or ft | M1 | For collecting $a$ terms on one side, remaining terms on other; ft only if two $a$ terms |
| $a(3-c) = 5f - 12$ or ft | M1 | For factorising $a$ terms; may be implied by final answer; ft only if two $a$ terms, needing factorising; may be earned before 2nd M1 |
| $\left[a =\right] \dfrac{5f-12}{3-c}$ oe or ft as final answer | M1 | For division by their two-term factor; for all 4 marks to be earned, work must be fully correct |
| | **[4]** | |

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5 Make $a$ the subject of $3 ( a + 4 ) = a c + 5 f$.

\hfill \mbox{\textit{OCR MEI C1 2014 Q5 [4]}}