CAIE P1 2024 March — Question 4 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2024
SessionMarch
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeProve identity then solve
DifficultyModerate -0.3 Part (a) is a straightforward algebraic manipulation of a trigonometric identity requiring expansion of brackets and use of sin²θ + cos²θ = 1. Part (b) uses the result to solve a cubic equation in tan θ, which factors easily to give tan θ = 0 or tan²θ = 2/5. This is a standard two-part question slightly easier than average due to the routine algebraic techniques and straightforward solving process.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05p Proof involving trig: functions and identities

4
  1. Prove that \(\frac { ( \sin \theta + \cos \theta ) ^ { 2 } - 1 } { \cos ^ { 2 } \theta } \equiv 2 \tan \theta\). \includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_63_1569_333_328} .............................................................................................................................................. \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_65_1570_511_324} \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_62_1570_603_324} \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_685_324} \includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_776_324} ...................................................................................................................................... . \includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_76_1572_952_322} ........................................................................................................................................ \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_1137_324} \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_74_1572_1226_322} \includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_77_1575_1315_319}
  2. Hence solve the equation \(\frac { ( \sin \theta + \cos \theta ) ^ { 2 } - 1 } { \cos ^ { 2 } \theta } = 5 \tan ^ { 3 } \theta\) for \(- 90 ^ { \circ } < \theta < 90 ^ { \circ }\).

Question 4(a):
AnswerMarks Guidance
AnswerMarks Guidance
Expand bracket to obtain 3 terms and use correct identityM1 \(\theta\) may be missing or another symbol used.
Use identity \(\frac{\sin\theta}{\cos\theta} = \tan\theta\)M1 Does not require any further explanation. \(\theta\) may be missing or another symbol used.
Conclude with \(2\tan\theta\)A1 WWW, AG
Total: 3
Question 4(b):
AnswerMarks Guidance
AnswerMarks Guidance
Attempt solution of \(5\tan^3\theta = 2\tan\theta\) to obtain at least one value of \(\tan\theta\)M1 SOI. Can be awarded if \(\tan\theta\) is cancelled and ignored.
Obtain at least two of \(0, \pm 32.3\)A1 Or greater accuracy. SC B1 if no method shown.
Obtain all three valuesA1 Or greater accuracy; and no others in \(-90°< \theta < 90°\) range. Other units SC B1 only for all 3 angles. SC B1 if no method shown.
Total: 3
## Question 4(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Expand bracket to obtain 3 terms and use correct identity | M1 | $\theta$ may be missing or another symbol used. |
| Use identity $\frac{\sin\theta}{\cos\theta} = \tan\theta$ | M1 | Does not require any further explanation. $\theta$ may be missing or another symbol used. |
| Conclude with $2\tan\theta$ | A1 | WWW, AG |
| **Total: 3** | | |

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## Question 4(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Attempt solution of $5\tan^3\theta = 2\tan\theta$ to obtain at least one value of $\tan\theta$ | M1 | SOI. Can be awarded if $\tan\theta$ is cancelled and ignored. |
| Obtain at least two of $0, \pm 32.3$ | A1 | Or greater accuracy. **SC B1** if no method shown. |
| Obtain all three values | A1 | Or greater accuracy; and no others in $-90°< \theta < 90°$ range. Other units **SC B1** only for all 3 angles. **SC B1** if no method shown. |
| **Total: 3** | | |

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4
\begin{enumerate}[label=(\alph*)]
\item Prove that $\frac { ( \sin \theta + \cos \theta ) ^ { 2 } - 1 } { \cos ^ { 2 } \theta } \equiv 2 \tan \theta$.\\
\includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_63_1569_333_328} ..............................................................................................................................................\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_65_1570_511_324}\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_62_1570_603_324}\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_685_324}\\
\includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_776_324} ...................................................................................................................................... .\\
\includegraphics[max width=\textwidth, alt={}]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_76_1572_952_322} ........................................................................................................................................\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_72_1570_1137_324}\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_74_1572_1226_322}\\
\includegraphics[max width=\textwidth, alt={}, center]{b5eb378d-a9cb-40e0-9203-374b58f1dcf9-05_77_1575_1315_319}
\item Hence solve the equation $\frac { ( \sin \theta + \cos \theta ) ^ { 2 } - 1 } { \cos ^ { 2 } \theta } = 5 \tan ^ { 3 } \theta$ for $- 90 ^ { \circ } < \theta < 90 ^ { \circ }$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2024 Q4 [6]}}