OCR C1 2010 June — Question 8 10 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Year2010
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSolving quadratics and applications
TypeCompleting the square, form and properties
DifficultyModerate -0.8 This is a straightforward multi-part question testing routine completing-the-square technique, reading minimum point coordinates, and solving a basic quadratic inequality by factorization. All parts are standard textbook exercises requiring only procedural knowledge with no problem-solving insight needed.
Spec1.02e Complete the square: quadratic polynomials and turning points1.02g Inequalities: linear and quadratic in single variable1.07m Tangents and normals: gradient and equations1.07n Stationary points: find maxima, minima using derivatives

8
  1. Express \(2 x ^ { 2 } + 5 x\) in the form \(2 ( x + p ) ^ { 2 } + q\).
  2. State the coordinates of the minimum point of the curve \(y = 2 x ^ { 2 } + 5 x\).
  3. State the equation of the normal to the curve at its minimum point.
  4. Solve the inequality \(2 x ^ { 2 } + 5 x > 0\).

Question 8:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(2(x^2 + \frac{5}{2}x)\)B1 \(\left(x + \frac{5}{4}\right)^2\)
\(= 2\left[\left(x+\frac{5}{4}\right)^2 - \frac{25}{16}\right]\)M1 \(q = -2p^2\)
\(= 2\left(x+\frac{5}{4}\right)^2 - \frac{25}{8}\)A1 3 \(q = -\frac{25}{8}\) c.w.o.
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\left(-\frac{5}{4}, -\frac{25}{8}\right)\)B1\(\checkmark\) B1\(\checkmark\) 2
Part (iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x = -\frac{5}{4}\)B1 1
Part (iv):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x(2x+5) > 0\)M1 Correct method to find roots
A1\(0, -\frac{5}{2}\) seen
\(x < -\frac{5}{2},\ x > 0\)M1 Correct method to solve quadratic inequality
A14 (not wrapped, strict inequalities, no 'and')
# Question 8:

## Part (i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $2(x^2 + \frac{5}{2}x)$ | B1 | $\left(x + \frac{5}{4}\right)^2$ |
| $= 2\left[\left(x+\frac{5}{4}\right)^2 - \frac{25}{16}\right]$ | M1 | $q = -2p^2$ |
| $= 2\left(x+\frac{5}{4}\right)^2 - \frac{25}{8}$ | A1 | **3** $q = -\frac{25}{8}$ c.w.o. |

## Part (ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\left(-\frac{5}{4}, -\frac{25}{8}\right)$ | B1$\checkmark$ B1$\checkmark$ | **2** |

## Part (iii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $x = -\frac{5}{4}$ | B1 | **1** |

## Part (iv):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $x(2x+5) > 0$ | M1 | Correct method to find roots |
| | A1 | $0, -\frac{5}{2}$ seen |
| $x < -\frac{5}{2},\ x > 0$ | M1 | Correct method to solve quadratic inequality |
| | A1 | **4** (not wrapped, strict inequalities, no 'and') |

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8 (i) Express $2 x ^ { 2 } + 5 x$ in the form $2 ( x + p ) ^ { 2 } + q$.\\
(ii) State the coordinates of the minimum point of the curve $y = 2 x ^ { 2 } + 5 x$.\\
(iii) State the equation of the normal to the curve at its minimum point.\\
(iv) Solve the inequality $2 x ^ { 2 } + 5 x > 0$.

\hfill \mbox{\textit{OCR C1 2010 Q8 [10]}}