CAIE S1 2020 Specimen — Question 3 7 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2020
SessionSpecimen
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeCalculate Var(X) from table
DifficultyModerate -0.5 This is a straightforward variance calculation from a probability distribution table that students have already constructed. Once the table is drawn in part (b) and E(X) is given, finding Var(X) requires only the standard formula Var(X) = E(X²) - [E(X)]², involving basic arithmetic with small numbers. This is a routine textbook exercise testing recall of the variance formula rather than problem-solving.
Spec2.04a Discrete probability distributions5.02b Expectation and variance: discrete random variables

3 A book club sends 6 paperback and 2 hardback books to Mrs Hunt. She chooses 4 of these books at random to take with her on holiday. The random variable \(X\) represents the number of paperback books she chooses.
  1. Show that the probability that she chooses exactly 2 paperback books is \(\frac { 3 } { 14 }\).
  2. Draw up the probability distribution table for \(X\).
  3. You are given that \(\mathrm { E } ( X ) = 3\). Find \(\operatorname { Var } ( X )\).

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
EITHER Solution 1: \(P(\text{exactly } 2) = \frac{^6C_2 \cdot ^2C_2}{^8C_4}\)(M1) \(\frac{^6C_x}{^8C_y}\) seen
\(= \frac{15}{70} = \frac{3}{14}\)A1) AG CWO
OR Solution 2: \(P(2) = \frac{6}{8} \times \frac{5}{7} \times \frac{2}{6} \times {}^4C_2\)(M1) \({}^4C_x\) multiplied by 4 fractions
\(= \frac{3}{14}\)A1) AG CWO
Total: 2 marks
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(x\): 2, 3, 4B1 2, 3, 4 only in top line
Prob: \(\frac{3}{14}\), \(\frac{8}{14}\), \(\frac{3}{14}\)B1 one correct probability other than \(P(2)\)
(third row correct)B1FT third correct probability \(FT\ \Sigma = 1\)
Total: 3 marks
Question 3(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(\text{Var}(X) = \frac{12}{14} + \frac{72}{14} + \frac{48}{14} - 3^2\)M1 using \(\Sigma x^2 p - 3^2\)
\(= \frac{3}{7} = 0.429\)A1
Total: 2 marks
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| **EITHER** Solution 1: $P(\text{exactly } 2) = \frac{^6C_2 \cdot ^2C_2}{^8C_4}$ | (M1) | $\frac{^6C_x}{^8C_y}$ seen |
| $= \frac{15}{70} = \frac{3}{14}$ | A1) | AG CWO |
| **OR** Solution 2: $P(2) = \frac{6}{8} \times \frac{5}{7} \times \frac{2}{6} \times {}^4C_2$ | (M1) | ${}^4C_x$ multiplied by 4 fractions |
| $= \frac{3}{14}$ | A1) | AG CWO |

**Total: 2 marks**

---

## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $x$: 2, 3, 4 | B1 | 2, 3, 4 only in top line |
| Prob: $\frac{3}{14}$, $\frac{8}{14}$, $\frac{3}{14}$ | B1 | one correct probability other than $P(2)$ |
| (third row correct) | B1FT | third correct probability $FT\ \Sigma = 1$ |

**Total: 3 marks**

---

## Question 3(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\text{Var}(X) = \frac{12}{14} + \frac{72}{14} + \frac{48}{14} - 3^2$ | M1 | using $\Sigma x^2 p - 3^2$ |
| $= \frac{3}{7} = 0.429$ | A1 | |

**Total: 2 marks**

---
3 A book club sends 6 paperback and 2 hardback books to Mrs Hunt. She chooses 4 of these books at random to take with her on holiday. The random variable $X$ represents the number of paperback books she chooses.\\
(a) Show that the probability that she chooses exactly 2 paperback books is $\frac { 3 } { 14 }$.\\
(b) Draw up the probability distribution table for $X$.\\
(c) You are given that $\mathrm { E } ( X ) = 3$.

Find $\operatorname { Var } ( X )$.\\

\hfill \mbox{\textit{CAIE S1 2020 Q3 [7]}}