OCR FP3 2013 January — Question 2 6 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Year2013
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGroups
TypeOrder of elements
DifficultyStandard +0.8 This is a Further Maths group theory question requiring understanding of modular arithmetic with complex numbers. Part (i) is straightforward recall, part (ii) requires basic calculation, but part (iii) demands proof that all non-zero elements have order 5, requiring systematic reasoning about the structure of Z₅ × Z₅. The combination of abstract algebra concepts with modular arithmetic places this above average difficulty, though it's a standard FP3 exercise rather than requiring deep insight.
Spec8.03c Group definition: recall and use, show structure is/isn't a group8.03e Order of elements: and order of groups

2 The elements of a group \(G\) are the complex numbers \(a + b \mathrm { i }\) where \(a , b \in \{ 0,1,2,3,4 \}\). These elements are combined under the operation of addition modulo 5 .
  1. State the identity element and the order of \(G\).
  2. Write down the inverse of \(2 + 4 \mathrm { i }\).
  3. Show that every non-zero element of \(G\) has order 5 .

Question 2:
Part (i)
AnswerMarks Guidance
AnswerMarks Guidance
identity \(0+0i\)B1 Or '\(0\)'
order \(25\)B1
Part (ii)
AnswerMarks Guidance
AnswerMarks Guidance
\(3+i\)B1
Part (iii)
AnswerMarks Guidance
AnswerMarks Guidance
\(5(a+bi)=5a+5bi=0+0i\)M1 Shows 5 times any element equals \(e\)
every non-zero element has order 5 or 25M1 Attempt to show that order \(\neq 2,3,4\)
So order is 5A1 Argument is convincing, exhaustive and conclusive; must consider all non-zero elements
# Question 2:

## Part (i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| identity $0+0i$ | B1 | Or '$0$' |
| order $25$ | B1 | |

## Part (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $3+i$ | B1 | |

## Part (iii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $5(a+bi)=5a+5bi=0+0i$ | M1 | Shows 5 times any element equals $e$ |
| every non-zero element has order 5 or 25 | M1 | Attempt to show that order $\neq 2,3,4$ |
| So order is 5 | A1 | Argument is convincing, exhaustive and conclusive; must consider all non-zero elements |

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2 The elements of a group $G$ are the complex numbers $a + b \mathrm { i }$ where $a , b \in \{ 0,1,2,3,4 \}$. These elements are combined under the operation of addition modulo 5 .\\
(i) State the identity element and the order of $G$.\\
(ii) Write down the inverse of $2 + 4 \mathrm { i }$.\\
(iii) Show that every non-zero element of $G$ has order 5 .

\hfill \mbox{\textit{OCR FP3 2013 Q2 [6]}}