Edexcel AEA 2017 Specimen — Question 4 13 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2017
SessionSpecimen
Marks13
PaperDownload PDF ↗
TopicMotion on a slope
TypeString at angle to slope
DifficultyChallenging +1.8 This is an AEA mechanics problem requiring resolution of forces in two directions, friction analysis in multiple cases, and compound angle manipulation to reach a specific inverse trig form. While systematic, it demands careful case analysis (friction up/down/zero), non-trivial trigonometry with tan α = 3/4, and algebraic manipulation to match the given answer in part (b). More demanding than standard A-level mechanics but follows established methods without requiring novel geometric insight.
Spec3.03m Equilibrium: sum of resolved forces = 03.03t Coefficient of friction: F <= mu*R model3.03u Static equilibrium: on rough surfaces

4. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{05b21c5d-5958-4267-b1e6-3d1ed20d5609-12_428_897_251_593} \captionsetup{labelformat=empty} \caption{Figure 2}
\end{figure} A particle of weight \(W\) lies on a rough plane.The plane is inclined to the horizontal at an angle \(\alpha\) where \(\tan \alpha = \frac { 3 } { 4 }\) .The coefficient of friction between the particle and the plane is \(\frac { 1 } { 2 }\) The particle is held in equilibrium by a force of magnitude 1.2 W .The force makes an angle \(\theta\) with the plane,where \(0 < \theta < \pi\) ,and acts in a vertical plane containing a line of greatest slope of the plane,as shown in Figure 2.
  1. Find the value of \(\theta\) for which there is no frictional force acting on the particle. The minimum value of \(\theta\) for the particle to remain in equilibrium is \(\beta\)
  2. Show that $$\beta = \arccos \left( \frac { \sqrt { 5 } } { 3 } \right) - \arctan \left( \frac { 1 } { 2 } \right)$$
  3. Find the range of values of \(\theta\) for which the particle remains in equilibrium with the frictional force acting up the plane.

4.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{05b21c5d-5958-4267-b1e6-3d1ed20d5609-12_428_897_251_593}
\captionsetup{labelformat=empty}
\caption{Figure 2}
\end{center}
\end{figure}

A particle of weight $W$ lies on a rough plane.The plane is inclined to the horizontal at an angle $\alpha$ where $\tan \alpha = \frac { 3 } { 4 }$ .The coefficient of friction between the particle and the plane is $\frac { 1 } { 2 }$ The particle is held in equilibrium by a force of magnitude 1.2 W .The force makes an angle $\theta$ with the plane,where $0 < \theta < \pi$ ,and acts in a vertical plane containing a line of greatest slope of the plane,as shown in Figure 2.
\begin{enumerate}[label=(\alph*)]
\item Find the value of $\theta$ for which there is no frictional force acting on the particle.

The minimum value of $\theta$ for the particle to remain in equilibrium is $\beta$
\item Show that

$$\beta = \arccos \left( \frac { \sqrt { 5 } } { 3 } \right) - \arctan \left( \frac { 1 } { 2 } \right)$$
\item Find the range of values of $\theta$ for which the particle remains in equilibrium with the frictional force acting up the plane.
\end{enumerate}

\hfill \mbox{\textit{Edexcel AEA 2017 Q4 [13]}}