CAIE P3 2011 June — Question 2 4 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2011
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeFind stationary points - logarithmic functions
DifficultyModerate -0.3 This is a straightforward application of the quotient rule to find dy/dx, then solving dy/dx = 0. The algebra is clean (numerator gives 1 - 3ln x = 0), leading directly to x = e^(1/3). Slightly easier than average as it's a single-step problem with standard technique and simple algebraic manipulation.
Spec1.07l Derivative of ln(x): and related functions1.07n Stationary points: find maxima, minima using derivatives1.07q Product and quotient rules: differentiation

2 The curve \(y = \frac { \ln x } { x ^ { 3 } }\) has one stationary point. Find the \(x\)-coordinate of this point.

AnswerMarks Guidance
Use correct quotient or product ruleM1
Obtain correct derivative in any form, e.g. \(-\frac{3\ln x}{x^2} + \frac{1}{x^3}\)A1
Equate derivative to zero and solve for \(x\) an equation of the form \(\ln x = a\), where \(a > 0\)M1
Obtain answer \(\exp\left(\frac{5}{3}\right)\), or 1.40, from correct workA1 [4]
Use correct quotient or product rule | M1 |
Obtain correct derivative in any form, e.g. $-\frac{3\ln x}{x^2} + \frac{1}{x^3}$ | A1 |
Equate derivative to zero and solve for $x$ an equation of the form $\ln x = a$, where $a > 0$ | M1 |
Obtain answer $\exp\left(\frac{5}{3}\right)$, or 1.40, from correct work | A1 | [4]
2 The curve $y = \frac { \ln x } { x ^ { 3 } }$ has one stationary point. Find the $x$-coordinate of this point.

\hfill \mbox{\textit{CAIE P3 2011 Q2 [4]}}