OCR S4 2016 June — Question 1 8 marks

Exam BoardOCR
ModuleS4 (Statistics 4)
Year2016
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicWilcoxon tests
TypeSign test
DifficultyModerate -0.8 This is a straightforward application of the sign test with clear data and standard hypothesis testing procedure. Part (i) requires counting signs and comparing to critical values from tables (routine S4 content), while part (ii) tests basic understanding of test comparison. The question is easier than average A-level as it's purely procedural with no problem-solving or novel insight required.
Spec5.07a Non-parametric tests: when to use5.07b Sign test: and Wilcoxon signed-rank5.07c Single-sample tests

1 Ten archers shot at targets with two types of bow. Their scores out of 100 are shown in the table.
Archer\(A\)\(B\)\(C\)\(D\)\(E\)\(F\)\(G\)\(H\)\(I\)\(J\)
Bow type \(P\)95979285879290899877
Bow type \(Q\)91918890808893859484
  1. Use the sign test, at the \(5 \%\) level of significance, to test the hypothesis that bow type \(P\) is better than bow type \(Q\).
  2. Why would a Wilcoxon signed rank test, if valid, be a better test than the sign test?

Question 1:
Part (i):
AnswerMarks Guidance
AnswerMarks Guidance
\(H_0: p = \frac{1}{2}\), \(H_1: p > \frac{1}{2}\)B1 For both. Allow any sensible hypotheses
Find signs of differencesM1 \(+++-++-++-\) or vv or vv
Obtain 7+, 3-A1
Attempt \(P(X \geq 7)\) or \(P(X \leq 3)\)M1ft
0.1719A1ft Allow 0.172 (0.0547 from 8+)
"0.1719" \(> 0.05\), so do not reject \(H_0\)M1 Ft candidate's \(p\). In context, not over-assertive. Cwo
Insufficient evidence that type P is betterA1 Attempt to find CR. M1 (not ft) \(X \geq 9\) or \(X \leq 1\) A1 (not ft); "7" (or "3") not in CR, so d.n.r. \(H_0\) ft; NOT "suff evidence that there is no difference between the bows."
[7]
Part (ii):
AnswerMarks Guidance
AnswerMarks Guidance
Magnitude of differences taken into accountB1 Uses more information. More powerful
[1]
# Question 1:

## Part (i):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $H_0: p = \frac{1}{2}$, $H_1: p > \frac{1}{2}$ | B1 | For both. Allow any sensible hypotheses |
| Find signs of differences | M1 | $+++-++-++-$ or vv or vv |
| Obtain 7+, 3- | A1 | |
| Attempt $P(X \geq 7)$ or $P(X \leq 3)$ | M1ft | |
| 0.1719 | A1ft | Allow 0.172 (0.0547 from 8+) |
| "0.1719" $> 0.05$, so do not reject $H_0$ | M1 | Ft candidate's $p$. In context, not over-assertive. Cwo |
| Insufficient evidence that type P is better | A1 | Attempt to find CR. M1 (not ft) $X \geq 9$ or $X \leq 1$ A1 (not ft); "7" (or "3") not in CR, so d.n.r. $H_0$ ft; NOT "suff evidence that there is no difference between the bows." |
| **[7]** | | |

## Part (ii):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Magnitude of differences taken into account | B1 | Uses more information. More powerful |
| **[1]** | | |

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1 Ten archers shot at targets with two types of bow. Their scores out of 100 are shown in the table.

\begin{center}
\begin{tabular}{ | l | c | c | c | c | c | c | c | c | c | c | }
\hline
Archer & $A$ & $B$ & $C$ & $D$ & $E$ & $F$ & $G$ & $H$ & $I$ & $J$ \\
\hline
Bow type $P$ & 95 & 97 & 92 & 85 & 87 & 92 & 90 & 89 & 98 & 77 \\
\hline
Bow type $Q$ & 91 & 91 & 88 & 90 & 80 & 88 & 93 & 85 & 94 & 84 \\
\hline
\end{tabular}
\end{center}

(i) Use the sign test, at the $5 \%$ level of significance, to test the hypothesis that bow type $P$ is better than bow type $Q$.\\
(ii) Why would a Wilcoxon signed rank test, if valid, be a better test than the sign test?

\hfill \mbox{\textit{OCR S4 2016 Q1 [8]}}