CAIE P3 2011 June — Question 4 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2011
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeSolve p(exponential) = 0
DifficultyStandard +0.3 This is a straightforward application of the factor theorem followed by a substitution problem. Part (i) involves routine verification and polynomial factorization (likely by inspection or algebraic division after finding one factor). Part (ii) requires recognizing that substituting x = 3^y transforms the exponential equation into f(x) = 0, then using logarithms to find y. While it requires connecting two ideas, both steps are standard techniques with no novel insight needed, making it slightly easier than average.
Spec1.02f Solve quadratic equations: including in a function of unknown1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.06g Equations with exponentials: solve a^x = b

4 The polynomial \(\mathrm { f } ( x )\) is defined by $$f ( x ) = 12 x ^ { 3 } + 25 x ^ { 2 } - 4 x - 12$$
  1. Show that \(\mathrm { f } ( - 2 ) = 0\) and factorise \(\mathrm { f } ( x )\) completely.
  2. Given that $$12 \times 27 ^ { y } + 25 \times 9 ^ { y } - 4 \times 3 ^ { y } - 12 = 0$$ state the value of \(3 ^ { y }\) and hence find \(y\) correct to 3 significant figures.

Question 4:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Verify that \(-96 + 100 + 8 - 12 = 0\)B1
Attempt to find quadratic factor by division by \((x+2)\), reaching partial quotient \(12x^2 + kx\), inspection or use of identityM1
Obtain \(12x^2 + x - 6\)A1
State \((x+2)(4x+3)(3x-2)\)A1 [4]
Note: M1 can be earned if inspection has unknown factor \(Ax^2 + Bx - 6\) and an equation in \(A\) and/or \(B\) or equation \(12x^2 + Bx + C\) and an equation in \(B\) and/or \(C\).
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
State \(3^y = \frac{2}{3}\) and no other valueB1
Use correct method for finding \(y\) from equation of form \(3^y = k\), where \(k > 0\)M1
Obtain \(-0.369\) and no other valueA1 [3]
## Question 4:

### Part (i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Verify that $-96 + 100 + 8 - 12 = 0$ | B1 | |
| Attempt to find quadratic factor by division by $(x+2)$, reaching partial quotient $12x^2 + kx$, inspection or use of identity | M1 | |
| Obtain $12x^2 + x - 6$ | A1 | |
| State $(x+2)(4x+3)(3x-2)$ | A1 | [4] |

**Note:** M1 can be earned if inspection has unknown factor $Ax^2 + Bx - 6$ and an equation in $A$ and/or $B$ or equation $12x^2 + Bx + C$ and an equation in $B$ and/or $C$.

### Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| State $3^y = \frac{2}{3}$ and no other value | B1 | |
| Use correct method for finding $y$ from equation of form $3^y = k$, where $k > 0$ | M1 | |
| Obtain $-0.369$ and no other value | A1 | [3] |

---
4 The polynomial $\mathrm { f } ( x )$ is defined by

$$f ( x ) = 12 x ^ { 3 } + 25 x ^ { 2 } - 4 x - 12$$

(i) Show that $\mathrm { f } ( - 2 ) = 0$ and factorise $\mathrm { f } ( x )$ completely.\\
(ii) Given that

$$12 \times 27 ^ { y } + 25 \times 9 ^ { y } - 4 \times 3 ^ { y } - 12 = 0$$

state the value of $3 ^ { y }$ and hence find $y$ correct to 3 significant figures.

\hfill \mbox{\textit{CAIE P3 2011 Q4 [7]}}