OCR MEI C4 — Question 4 5 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeRotation about y-axis, standard curve
DifficultyStandard +0.3 This is a straightforward volume of revolution about the y-axis question requiring students to rearrange y = 4 - x² to get x² in terms of y, identify the correct limits (y from 0 to 4), and apply the standard formula V = π∫x²dy. While it requires multiple steps, all are routine applications of a standard technique with no conceptual challenges, making it slightly easier than average.
Spec4.08d Volumes of revolution: about x and y axes

4 The part of the curve \(y = 4 - x ^ { 2 }\) that is above the \(x\)-axis is rotated about the \(y\)-axis. This is shown in Fig. 4. Find the volume of revolution produced, giving your answer in terms of \(\pi\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{8d786d33-c5c2-44a6-8273-7a3e43e552ef-3_534_595_1831_785} \captionsetup{labelformat=empty} \caption{Fig. 4}
\end{figure}

Question 4:
AnswerMarks Guidance
AnswerMarks Guidance
When \(x = 0\), \(y = 4\)B1
\(\Rightarrow V = \pi\int_0^4 x^2\,dy\)M1 must have integral, \(\pi\), \(x^2\) and \(dy\) soi
\(= \pi\int_0^4(4-y)\,dy\)M1 must have \(\pi\), their \((4-y)\), their numerical \(y\) limits
\(= \pi\left[4y - \frac{1}{2}y^2\right]_0^4\)B1 \(\left[4y - \frac{y^2}{2}\right]\)
\(= \pi(16 - 8) = 8\pi\)A1
[5]
## Question 4:

| Answer | Marks | Guidance |
|--------|-------|----------|
| When $x = 0$, $y = 4$ | B1 | |
| $\Rightarrow V = \pi\int_0^4 x^2\,dy$ | M1 | must have integral, $\pi$, $x^2$ and $dy$ soi |
| $= \pi\int_0^4(4-y)\,dy$ | M1 | must have $\pi$, their $(4-y)$, their numerical $y$ limits |
| $= \pi\left[4y - \frac{1}{2}y^2\right]_0^4$ | B1 | $\left[4y - \frac{y^2}{2}\right]$ |
| $= \pi(16 - 8) = 8\pi$ | A1 | |
| **[5]** | | |

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4 The part of the curve $y = 4 - x ^ { 2 }$ that is above the $x$-axis is rotated about the $y$-axis. This is shown in Fig. 4.

Find the volume of revolution produced, giving your answer in terms of $\pi$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{8d786d33-c5c2-44a6-8273-7a3e43e552ef-3_534_595_1831_785}
\captionsetup{labelformat=empty}
\caption{Fig. 4}
\end{center}
\end{figure}

\hfill \mbox{\textit{OCR MEI C4  Q4 [5]}}