| Exam Board | OCR MEI |
|---|---|
| Module | C4 (Core Mathematics 4) |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Numerical integration |
| Type | Complete table then apply trapezium rule |
| Difficulty | Moderate -0.3 This is a straightforward application of the trapezium rule requiring only calculator work to complete the table (evaluating √(cos x) at three points) and then applying the standard trapezium rule formula. Part (ii) tests basic understanding of trapezium rule over/under-estimation for concave curves. While it involves multiple steps, each is routine and requires no problem-solving insight—slightly easier than average due to its procedural nature. |
| Spec | 1.09f Trapezium rule: numerical integration |
| \(X\) | 0 | \(\frac { \pi } { 8 }\) | \(\frac { \pi } { 4 }\) | \(\frac { 3 \pi } { 8 }\) | \(\frac { \pi } { 2 }\) |
| \(y\) | 0.9612 | 0.8409 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(1, 0.6186, 0\) | B1 | 4dp (or more) |
| \(A \approx \frac{\pi}{16}\{1 + 0 + 2(0.9612 + 0.8409 + 0.6186)\}\) | M1 | ft their table; need to see trapezium rule |
| \(= 1.147\) (3 dp) | A1 [3] | cao |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| The estimate will increase, because the trapezia will be below but closer to the curve, reducing the error. | B1 [1] | o.e., or an illustration using the curve; full answer required |
# Question 4:
## Part (i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $1, 0.6186, 0$ | B1 | 4dp (or more) |
| $A \approx \frac{\pi}{16}\{1 + 0 + 2(0.9612 + 0.8409 + 0.6186)\}$ | M1 | ft their table; need to see trapezium rule |
| $= 1.147$ (3 dp) | A1 [3] | cao |
## Part (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| The estimate will increase, because the trapezia will be below but closer to the curve, reducing the error. | B1 [1] | o.e., or an illustration using the curve; full answer required |
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4 (i) Complete the table of values for the curve $y = \sqrt { \cos x }$.
\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
$X$ & 0 & $\frac { \pi } { 8 }$ & $\frac { \pi } { 4 }$ & $\frac { 3 \pi } { 8 }$ & $\frac { \pi } { 2 }$ \\
\hline
$y$ & & 0.9612 & 0.8409 & & \\
\hline
\end{tabular}
\end{center}
Hence use the trapezium rule with strip width $h = \frac { \pi } { 8 }$ to estimate the value of the integral $\int _ { 0 } ^ { \frac { \pi } { 2 } } \sqrt { \cos x } \mathrm {~d} x$, giving your answer to 3 decimal places.
Fig. 4 shows the curve $y = \sqrt { \cos x }$ for $0 \leqslant x \leqslant \frac { \pi } { 2 }$.
\begin{figure}[h]
\begin{center}
\includegraphics[alt={},max width=\textwidth]{ce44db53-2ec8-497b-a1d5-a8adf85e3929-4_459_751_799_638}
\captionsetup{labelformat=empty}
\caption{Fig. 4}
\end{center}
\end{figure}
(ii) State, with a reason, whether the trapezium rule with a strip width of $\frac { \pi } { 16 }$ would give a larger or smaller estimate of the integral.
\hfill \mbox{\textit{OCR MEI C4 Q4 [4]}}