OCR C4 — Question 5 9 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeEquation of tangent line
DifficultyStandard +0.3 Part (i) requires implicit differentiation with a trigonometric function and algebraic manipulation using trig identities, which is standard C4 material. Part (ii) is a routine chain rule application to find a tangent equation. Both parts are straightforward applications of techniques with no novel problem-solving required, making this slightly easier than average.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.07l Derivative of ln(x): and related functions1.07m Tangents and normals: gradient and equations1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates

5. (i) Given that $$x = \sec \frac { y } { 2 } , \quad 0 \leq y < \pi$$ show that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 2 } { x \sqrt { x ^ { 2 } - 1 } }$$ (ii) Find an equation for the tangent to the curve \(y = \sqrt { 3 + 2 \cos x }\) at the point where \(x = \frac { \pi } { 3 }\).

5. (i) Given that

$$x = \sec \frac { y } { 2 } , \quad 0 \leq y < \pi$$

show that

$$\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 2 } { x \sqrt { x ^ { 2 } - 1 } }$$

(ii) Find an equation for the tangent to the curve $y = \sqrt { 3 + 2 \cos x }$ at the point where $x = \frac { \pi } { 3 }$.\\

\hfill \mbox{\textit{OCR C4  Q5 [9]}}