OCR FP1 2013 June — Question 8 6 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2013
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeProduct expressions with roots
DifficultyStandard +0.8 This is a Further Maths question requiring manipulation of symmetric functions of roots beyond basic Vieta's formulas. Students must expand the expression algebraically, relate it to elementary symmetric functions (sum, sum of products, product of roots), then substitute using Vieta's formulas with careful coefficient handling. It's more sophisticated than standard A-level root problems but follows a recognizable FP1 pattern.
Spec4.05a Roots and coefficients: symmetric functions

8 The cubic equation \(k x ^ { 3 } + 6 x ^ { 2 } + x - 3 = 0\), where \(k\) is a non-zero constant, has roots \(\alpha , \beta\) and \(\gamma\).
Find the value of \(( \alpha + 1 ) ( \beta + 1 ) + ( \beta + 1 ) ( \gamma + 1 ) + ( \gamma + 1 ) ( \alpha + 1 )\) in terms of \(k\).

Question 8:
AnswerMarks Guidance
AnswerMarks Guidance
*Either:*
\(\sum\alpha = -\frac{6}{k},\ \sum\alpha\beta = \frac{1}{k}\)B1B1 Correct values stated or used
\(\sum\alpha\beta + 2\sum\alpha + 3\)M1 Expand brackets
A1Obtain correct expression aef
\(3 - \frac{11}{k}\)M1 Use their values, in terms of \(k\), for \(\sum\alpha\) and \(\sum\alpha\beta\)
A1Obtain correct answer aef
[6]
*Or:*
\(x = u - 1\)B1 State or use substitution \(x = u-1\)
M1Expand and attempt to simplify coefficients
\(ku^3 + (6-3k)u^2 + (3k-11)u + 2 - k = 0\)A1A1 Obtain at least correct \(1^{st}\) and \(3^{rd}\) terms
M1Use their \(\frac{c}{a}\)
\(3 - \frac{11}{k}\)A1 Obtain correct answer a.e.f.
## Question 8:

| Answer | Marks | Guidance |
|--------|-------|----------|
| *Either:* | | |
| $\sum\alpha = -\frac{6}{k},\ \sum\alpha\beta = \frac{1}{k}$ | B1B1 | Correct values stated or used |
| $\sum\alpha\beta + 2\sum\alpha + 3$ | M1 | Expand brackets |
| | A1 | Obtain correct expression aef |
| $3 - \frac{11}{k}$ | M1 | Use their values, in terms of $k$, for $\sum\alpha$ and $\sum\alpha\beta$ |
| | A1 | Obtain correct answer aef |
| **[6]** | | |
| *Or:* | | |
| $x = u - 1$ | B1 | State or use substitution $x = u-1$ |
| | M1 | Expand and attempt to simplify coefficients |
| $ku^3 + (6-3k)u^2 + (3k-11)u + 2 - k = 0$ | A1A1 | Obtain at least correct $1^{st}$ and $3^{rd}$ terms |
| | M1 | Use their $\frac{c}{a}$ |
| $3 - \frac{11}{k}$ | A1 | Obtain correct answer a.e.f. |

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8 The cubic equation $k x ^ { 3 } + 6 x ^ { 2 } + x - 3 = 0$, where $k$ is a non-zero constant, has roots $\alpha , \beta$ and $\gamma$.\\
Find the value of $( \alpha + 1 ) ( \beta + 1 ) + ( \beta + 1 ) ( \gamma + 1 ) + ( \gamma + 1 ) ( \alpha + 1 )$ in terms of $k$.

\hfill \mbox{\textit{OCR FP1 2013 Q8 [6]}}