OCR FP1 2006 June — Question 8 10 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2006
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
Topic3x3 Matrices
TypeParameter values for unique solution
DifficultyStandard +0.3 This is a standard Further Pure 1 question on matrix determinants and singularity. Part (i) requires routine calculation of a 3×3 determinant, part (ii) is direct application (setting det=0), and part (iii) tests understanding that singular matrices mean no unique solution. While it's Further Maths content, it follows a predictable template with no novel problem-solving required, making it slightly easier than average overall.
Spec4.03j Determinant 3x3: calculation4.03l Singular/non-singular matrices4.03r Solve simultaneous equations: using inverse matrix

8 The matrix \(\mathbf { M }\) is given by \(\mathbf { M } = \left( \begin{array} { l l l } a & 4 & 2 \\ 1 & a & 0 \\ 1 & 2 & 1 \end{array} \right)\).
  1. Find, in terms of \(a\), the determinant of \(\mathbf { M }\).
  2. Hence find the values of \(a\) for which \(\mathbf { M }\) is singular.
  3. State, giving a brief reason in each case, whether the simultaneous equations $$\begin{aligned} a x + 4 y + 2 z & = 3 a \\ x + a y & = 1 \\ x + 2 y + z & = 3 \end{aligned}$$ have any solutions when
    1. \(a = 3\),
    2. \(a = 2\).

AnswerMarks Guidance
Part (i) Expansion of \(a \begin{bmatrix} a & 0 \\ 2 & 1 \end{bmatrix} - 4 \begin{bmatrix} 1 & 0 \\ 1 & 1 \end{bmatrix} + 2 \begin{bmatrix} 1 & a \\ 1 & 2 \end{bmatrix}\)M1 Correct expansion process shown
A1Obtain correct unsimplified expression
A1, 3Obtain correct answer: \(a^2 - 2a\)
Part (ii) Set \(\det M = 0\)M1 Solve their \(\det M = 0\)
A1, A1, 1ft, 3Obtain correct answers: \(a = 0\) or \(a = 2\)
Part (iii) (a)B1, B1 Solution, as inverse matrix exists or \(M\) non-singular or \(\det M \neq 0\)
Part (iii) (b)B1, B1, 4 Solutions, eqn. 1 is multiple of eqn 3
**Part (i)** Expansion of $a \begin{bmatrix} a & 0 \\ 2 & 1 \end{bmatrix} - 4 \begin{bmatrix} 1 & 0 \\ 1 & 1 \end{bmatrix} + 2 \begin{bmatrix} 1 & a \\ 1 & 2 \end{bmatrix}$ | M1 | Correct expansion process shown
| A1 | Obtain correct unsimplified expression
| A1, 3 | Obtain correct answer: $a^2 - 2a$

**Part (ii)** Set $\det M = 0$ | M1 | Solve their $\det M = 0$
| A1, A1, 1ft, 3 | Obtain correct answers: $a = 0$ or $a = 2$

**Part (iii) (a)** | B1, B1 | Solution, as inverse matrix exists or $M$ non-singular or $\det M \neq 0$

**Part (iii) (b)** | B1, B1, 4 | Solutions, eqn. 1 is multiple of eqn 3
8 The matrix $\mathbf { M }$ is given by $\mathbf { M } = \left( \begin{array} { l l l } a & 4 & 2 \\ 1 & a & 0 \\ 1 & 2 & 1 \end{array} \right)$.\\
(i) Find, in terms of $a$, the determinant of $\mathbf { M }$.\\
(ii) Hence find the values of $a$ for which $\mathbf { M }$ is singular.\\
(iii) State, giving a brief reason in each case, whether the simultaneous equations

$$\begin{aligned}
a x + 4 y + 2 z & = 3 a \\
x + a y & = 1 \\
x + 2 y + z & = 3
\end{aligned}$$

have any solutions when
\begin{enumerate}[label=(\alph*)]
\item $a = 3$,
\item $a = 2$.
\end{enumerate}

\hfill \mbox{\textit{OCR FP1 2006 Q8 [10]}}