OCR FP1 2008 January — Question 3 4 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2008
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeSubstitution to find new equation
DifficultyStandard +0.3 This is a straightforward Further Maths question requiring mechanical substitution x=1/u (multiply through by u³) and then applying standard symmetric function relationships. Part (ii) follows directly from recognizing the required expression as a ratio of elementary symmetric functions from the transformed equation. While it's Further Maths content, the technique is routine and well-practiced.
Spec4.05b Transform equations: substitution for new roots

3 The cubic equation \(2 x ^ { 3 } - 3 x ^ { 2 } + 24 x + 7 = 0\) has roots \(\alpha , \beta\) and \(\gamma\).
  1. Use the substitution \(x = \frac { 1 } { u }\) to find a cubic equation in \(u\) with integer coefficients.
  2. Hence, or otherwise, find the value of \(\frac { 1 } { \alpha \beta } + \frac { 1 } { \beta \gamma } + \frac { 1 } { \gamma \alpha }\).

3 The cubic equation $2 x ^ { 3 } - 3 x ^ { 2 } + 24 x + 7 = 0$ has roots $\alpha , \beta$ and $\gamma$.\\
(i) Use the substitution $x = \frac { 1 } { u }$ to find a cubic equation in $u$ with integer coefficients.\\
(ii) Hence, or otherwise, find the value of $\frac { 1 } { \alpha \beta } + \frac { 1 } { \beta \gamma } + \frac { 1 } { \gamma \alpha }$.

\hfill \mbox{\textit{OCR FP1 2008 Q3 [4]}}