CAIE P3 2002 June — Question 1 3 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2002
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeDouble angle with reciprocal functions
DifficultyStandard +0.3 This is a straightforward identity proof requiring manipulation of reciprocal trig functions and application of the double angle formula. Students need to express cot and tan in terms of sin and cos, combine fractions, and recognize the double angle form—standard techniques for this topic with no novel insight required.
Spec1.01a Proof: structure of mathematical proof and logical steps1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05l Double angle formulae: and compound angle formulae

1 Prove the identity $$\cot \theta - \tan \theta \equiv 2 \cot 2 \theta$$

EITHER route:
AnswerMarks
Express LHS in terms of \(\cos\theta\) and \(\sin\theta\)M1
Make sufficient relevant use of double-angle formula(e)M1
Complete proof of the resultA1
OR route:
AnswerMarks Guidance
Express RHS in terms of \(\cos\theta\) and \(\sin\theta\) or in terms of \(\tan\theta\)M1
Express RHS as the difference (or sum) of two fractionsM1
Complete proof of the resultA1
Guidance: SR: an attempt ending with \(\frac{1-\tan^2\theta}{\tan\theta} = \cot\theta - \tan\theta\) earns M1 B1 only Total: 3 marks
**EITHER route:**
Express LHS in terms of $\cos\theta$ and $\sin\theta$ | M1 |
Make sufficient relevant use of double-angle formula(e) | M1 |
Complete proof of the result | A1 |

**OR route:**
Express RHS in terms of $\cos\theta$ and $\sin\theta$ or in terms of $\tan\theta$ | M1 |
Express RHS as the difference (or sum) of two fractions | M1 |
Complete proof of the result | A1 |

**Guidance:** SR: an attempt ending with $\frac{1-\tan^2\theta}{\tan\theta} = \cot\theta - \tan\theta$ earns M1 B1 only | | **Total: 3 marks**

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1 Prove the identity

$$\cot \theta - \tan \theta \equiv 2 \cot 2 \theta$$

\hfill \mbox{\textit{CAIE P3 2002 Q1 [3]}}