OCR C4 2008 January — Question 6 8 marks

Exam BoardOCR
ModuleC4 (Core Mathematics 4)
Year2008
SessionJanuary
Marks8
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Mark schemeDownload PDF ↗
TopicGeneralised Binomial Theorem
TypeTwo unknowns from two coefficient conditions
DifficultyStandard +0.3 This is a standard binomial expansion question requiring routine application of the formula followed by solving simultaneous equations. Part (i) is straightforward recall, and part (ii) involves algebraic manipulation of two equations in two unknowns—slightly above average due to the multi-step nature but still a textbook exercise with no novel insight required.
Spec1.04c Extend binomial expansion: rational n, |x|<11.04d Binomial expansion validity: convergence conditions

6
  1. Expand \(( 1 + a x ) ^ { - 4 }\) in ascending powers of \(x\), up to and including the term in \(x ^ { 2 }\).
  2. The coefficients of \(x\) and \(x ^ { 2 }\) in the expansion of \(( 1 + b x ) ( 1 + a x ) ^ { - 4 }\) are 1 and - 2 respectively. Given that \(a > 0\), find the values of \(a\) and \(b\).

AnswerMarks Guidance
(i) \(1 - 4ax + \ldots\)B1
\(\frac{-4,-5}{1.2}(ax)^2\) or \(\frac{-4,-5}{1.2}a^2x^2\) or \(\frac{-4,-5}{1.2}ax^2\)M1 Do not accept \(\begin{pmatrix}-4\\2\end{pmatrix}\) unless 10 also appears
\(\ldots + 10a^2x^2\)A1 3
(ii) f.t. (their of \(x\)) + \(b\)(their const cf) \(= 1\)\(\sqrt{B1}\) Expect \(b - 4a = 1\)
f.t. (their of \(x^2\)) + \(b\)(their of \(x\)) \(= -2\)\(\sqrt{B1}\) Expect \(10a^2 - 4ab = -2\) Or eliminate '\(a\)' and produce equation in '\(b\)' Or \(6b^2 + 4b = 42\)
Attempt to eliminate '\(b\)' and produce equation in '\(a\)'M1
Produce \(6a^2 + 4a = 2\)AEF
\(a = \frac{1}{3}\) and \(b = \frac{7}{3}\) onlyA1 5
(i) $1 - 4ax + \ldots$ | B1 | |
$\frac{-4,-5}{1.2}(ax)^2$ or $\frac{-4,-5}{1.2}a^2x^2$ or $\frac{-4,-5}{1.2}ax^2$ | M1 | Do not accept $\begin{pmatrix}-4\\2\end{pmatrix}$ unless 10 also appears |
$\ldots + 10a^2x^2$ | A1 | 3 |

(ii) f.t. (their of $x$) + $b$(their const cf) $= 1$ | $\sqrt{B1}$ | Expect $b - 4a = 1$ |
f.t. (their of $x^2$) + $b$(their of $x$) $= -2$ | $\sqrt{B1}$ | Expect $10a^2 - 4ab = -2$ Or eliminate '$a$' and produce equation in '$b$' Or $6b^2 + 4b = 42$ |
Attempt to eliminate '$b$' and produce equation in '$a$' | M1 | |
Produce $6a^2 + 4a = 2$ | AEF | |
$a = \frac{1}{3}$ and $b = \frac{7}{3}$ only | A1 | 5 | Made clear to be only (final) answer |
6 (i) Expand $( 1 + a x ) ^ { - 4 }$ in ascending powers of $x$, up to and including the term in $x ^ { 2 }$.\\
(ii) The coefficients of $x$ and $x ^ { 2 }$ in the expansion of $( 1 + b x ) ( 1 + a x ) ^ { - 4 }$ are 1 and - 2 respectively. Given that $a > 0$, find the values of $a$ and $b$.\\

\hfill \mbox{\textit{OCR C4 2008 Q6 [8]}}