CAIE P2 2015 June — Question 4

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2015
SessionJune
TopicStandard Integrals and Reverse Chain Rule

4
\includegraphics[max width=\textwidth, alt={}, center]{3b217eb4-3bd3-4800-a913-749754bf109f-2_524_625_1425_758} The diagram shows the curve \(y = \mathrm { e } ^ { x } + 4 \mathrm { e } ^ { - 2 x }\) and its minimum point \(M\).
  1. Show that the \(x\)-coordinate of \(M\) is \(\ln 2\).
  2. The region shaded in the diagram is enclosed by the curve and the lines \(x = 0 , x = \ln 2\) and \(y = 0\). Use integration to show that the area of the shaded region is \(\frac { 5 } { 2 }\).
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