OCR C3 2008 January — Question 1 5 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2008
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeEvaluate composite at point
DifficultyEasy -1.2 This is a straightforward question testing basic function composition and inverse function evaluation. Part (i) requires substituting x=1 into g, then that result into f—a simple two-step calculation. Part (ii) involves solving a cubic equation (x³+4=12) which simplifies to x³=8, giving x=2. Both parts are routine applications of definitions with minimal problem-solving required, making this easier than average.
Spec1.02v Inverse and composite functions: graphs and conditions for existence

1 Functions f and g are defined for all real values of \(x\) by $$\mathrm { f } ( x ) = x ^ { 3 } + 4 \quad \text { and } \quad \mathrm { g } ( x ) = 2 x - 5$$ Evaluate
  1. \(f g ( 1 )\),
  2. \(\mathrm { f } ^ { - 1 } ( 12 )\).

1 Functions f and g are defined for all real values of $x$ by

$$\mathrm { f } ( x ) = x ^ { 3 } + 4 \quad \text { and } \quad \mathrm { g } ( x ) = 2 x - 5$$

Evaluate\\
(i) $f g ( 1 )$,\\
(ii) $\mathrm { f } ^ { - 1 } ( 12 )$.

\hfill \mbox{\textit{OCR C3 2008 Q1 [5]}}