OCR C3 2006 January — Question 6 9 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2006
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Functions
TypeExponential growth/decay model setup
DifficultyModerate -0.3 This is a straightforward exponential model question requiring standard techniques: finding a constant from given values, solving a logarithmic equation, and differentiating an exponential function. All parts are routine C3 exercises with no problem-solving insight required, making it slightly easier than average but not trivial due to the multi-step nature.
Spec1.06g Equations with exponentials: solve a^x = b1.06h Logarithmic graphs: reduce y=ax^n and y=kb^x to linear form1.06i Exponential growth/decay: in modelling context1.07j Differentiate exponentials: e^(kx) and a^(kx)

6
  1. \(t\)01020
    \(X\)275440
    The quantity \(X\) is increasing exponentially with respect to time \(t\). The table above shows values of \(X\) for different values of \(t\). Find the value of \(X\) when \(t = 20\).
  2. The quantity \(Y\) is decreasing exponentially with respect to time \(t\) where $$Y = 80 \mathrm { e } ^ { - 0.02 t }$$
    1. Find the value of \(t\) for which \(Y = 20\), giving your answer correct to 2 significant figures.
    2. Find by differentiation the rate at which \(Y\) is decreasing when \(t = 30\), giving your answer correct to 2 significant figures.

Question 6(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Either: State proportion \(\frac{440}{275}\)B1
Attempt calculation involving proportionM1 Involving multiplication and \(X\) value
Obtain 704A1 3
Or: Use formula of form \(275e^{kt}\) or \(275a^t\)M1 Or equiv
Obtain \(k = 0.047\) or \(a = \sqrt[10]{1.6}\)A1 Or equiv
Obtain 704A1 (3) Allow \(\pm 0.5\)
Question 6(b)(i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Attempt correct process involving logarithmM1 Or equiv including systematic trial and improvement attempt
Obtain \(\ln\frac{20}{80} = -0.02t\)A1 Or equiv
Obtain 69A1 3 Or greater accuracy; scheme for T&I: M1A2
Question 6(b)(ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Differentiate to obtain \(ke^{-0.02t}\)M1 Any constant \(k\) different from 80
Obtain \(-1.6e^{-0.02t}\) (or \(1.6e^{-0.02t}\))A1 Or unsimplified equiv
Obtain 0.88A1 3 Or greater accuracy; allow \(-0.88\)
## Question 6(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Either: State proportion $\frac{440}{275}$ | B1 | |
| Attempt calculation involving proportion | M1 | Involving multiplication and $X$ value |
| Obtain 704 | A1 | **3** |
| Or: Use formula of form $275e^{kt}$ or $275a^t$ | M1 | Or equiv |
| Obtain $k = 0.047$ or $a = \sqrt[10]{1.6}$ | A1 | Or equiv |
| Obtain 704 | A1 | **(3)** Allow $\pm 0.5$ |

## Question 6(b)(i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Attempt correct process involving logarithm | M1 | Or equiv including systematic trial and improvement attempt |
| Obtain $\ln\frac{20}{80} = -0.02t$ | A1 | Or equiv |
| Obtain 69 | A1 | **3** Or greater accuracy; scheme for T&I: M1A2 |

## Question 6(b)(ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Differentiate to obtain $ke^{-0.02t}$ | M1 | Any constant $k$ different from 80 |
| Obtain $-1.6e^{-0.02t}$ (or $1.6e^{-0.02t}$) | A1 | Or unsimplified equiv |
| Obtain 0.88 | A1 | **3** Or greater accuracy; allow $-0.88$ |

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6
\begin{enumerate}[label=(\alph*)]
\item \begin{center}
\begin{tabular}{ | c | c | c | c | }
\hline
$t$ & 0 & 10 & 20 \\
\hline
$X$ & 275 & 440 &  \\
\hline
\end{tabular}
\end{center}

The quantity $X$ is increasing exponentially with respect to time $t$. The table above shows values of $X$ for different values of $t$. Find the value of $X$ when $t = 20$.
\item The quantity $Y$ is decreasing exponentially with respect to time $t$ where

$$Y = 80 \mathrm { e } ^ { - 0.02 t }$$
\begin{enumerate}[label=(\roman*)]
\item Find the value of $t$ for which $Y = 20$, giving your answer correct to 2 significant figures.
\item Find by differentiation the rate at which $Y$ is decreasing when $t = 30$, giving your answer correct to 2 significant figures.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{OCR C3 2006 Q6 [9]}}