OCR C3 2006 January — Question 2 5 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2006
SessionJanuary
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSolve equation using Pythagorean identities
DifficultyStandard +0.3 This is a standard C3 trigonometric equation requiring the Pythagorean identity sec²θ = 1 + tan²θ to convert to a quadratic in tan θ, then solving and finding angles in the given range. Slightly above average difficulty due to the use of sec/tan rather than sin/cos, but follows a well-practiced procedure with no novel insight required.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.05o Trigonometric equations: solve in given intervals

2 Solve, for \(0 ^ { \circ } < \theta < 360 ^ { \circ }\), the equation \(\sec ^ { 2 } \theta = 4 \tan \theta - 2\).

Question 2:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Attempt use of identity linking \(\sec^2\theta\), \(\tan^2\theta\) and 1M1 To write eqn in terms of \(\tan\theta\)
Obtain \(\tan^2\theta - 4\tan\theta + 3 = 0\)A1 Or correct unsimplified equiv
Attempt solution of quadratic eqn to find two values of \(\tan\theta\)M1 Any 3 term quadratic eqn in \(\tan\theta\)
Obtain at least two correct answersA1 After correct solution of eqn
Obtain all four of 45, 225, 71.6, 251.6A1 5 Allow greater accuracy or angles to nearest degree – and no other answers between 0 and 360
## Question 2:

| Answer/Working | Mark | Guidance |
|---|---|---|
| Attempt use of identity linking $\sec^2\theta$, $\tan^2\theta$ and 1 | M1 | To write eqn in terms of $\tan\theta$ |
| Obtain $\tan^2\theta - 4\tan\theta + 3 = 0$ | A1 | Or correct unsimplified equiv |
| Attempt solution of quadratic eqn to find two values of $\tan\theta$ | M1 | Any 3 term quadratic eqn in $\tan\theta$ |
| Obtain at least two correct answers | A1 | After correct solution of eqn |
| Obtain all four of 45, 225, 71.6, 251.6 | A1 | **5** Allow greater accuracy or angles to nearest degree – and no other answers between 0 and 360 |

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2 Solve, for $0 ^ { \circ } < \theta < 360 ^ { \circ }$, the equation $\sec ^ { 2 } \theta = 4 \tan \theta - 2$.

\hfill \mbox{\textit{OCR C3 2006 Q2 [5]}}