Edexcel M2 2022 October — Question 3 6 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2022
SessionOctober
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImpulse and momentum (advanced)
TypeVelocity after impulse (find unknown constant)
DifficultyStandard +0.3 This is a standard M2 impulse-momentum question requiring application of the impulse-momentum equation in vector form, followed by solving a quadratic equation using the speed condition. It involves routine algebraic manipulation with no novel insight required, making it slightly easier than average for A-level mechanics.
Spec1.10d Vector operations: addition and scalar multiplication6.03f Impulse-momentum: relation6.03g Impulse in 2D: vector form

  1. A particle \(P\) of mass 0.2 kg is moving with velocity \(( 4 \mathbf { i } - 3 \mathbf { j } ) \mathrm { ms } ^ { - 1 }\)
The particle receives an impulse \(\lambda ( \mathbf { i } + \mathbf { j } ) \mathrm { Ns }\), where \(\lambda\) is a constant.
Immediately after receiving the impulse, the speed of \(P\) is \(7 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) Find the possible values of \(\lambda\)

Question 3:
AnswerMarks Guidance
Answer/WorkingMark Guidance
Use of \(\mathbf{I} = m\mathbf{v} - m\mathbf{u}\)M1 Accept equivalent e.g. \(\mathbf{I}+m\mathbf{u}=m\mathbf{v}\). Dimensionally correct, must be using subtraction. Use of 7 in place of velocity in impulse-momentum equation is M0 unless they recover
\(0.2(\mathbf{v} - 4\mathbf{i} + 3\mathbf{j}) = \lambda(\mathbf{i}+\mathbf{j})\) leading to \(((x-4)\mathbf{i}+(y+3)\mathbf{j} = 5\lambda\mathbf{i}+5\lambda\mathbf{j})\)A1 Correct unsimplified vector equation or pair of separate equations for \(\mathbf{i}\) and \(\mathbf{j}\) components. Condone column vectors
Use of Pythagoras for the speedM1 Correct use of Pythagoras and 49 for their speed
\(x^2 + y^2 = 49\)A1 Correct unsimplified equation for their \(x\), \(y\)
Form quadratic in \(x\), \(y\) or \(\lambda\) and solve for \(\lambda\)DM1 Dependent on both previous M marks. \(x^2 + -(x-7)^2 = 49\) or \((y+7)^2 + y^2 = 49\) or \((5\lambda+4)^2 + (5\lambda-3)^2 = 49\)
\(\lambda = \dfrac{3}{5}\) or \(\lambda = -\dfrac{4}{5}\)A1 Or equivalent
Total: (6)
Alternative Method (Question 3):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Form vector triangleM1 Dimensionally correct. Allow incorrect configuration
Correct triangle and correct lengthsA1 In speeds or momentum but not a mixture
Use scalar product to find cosine of angleM1 Or equivalent method
\(\cos\theta = -\dfrac{1}{5\sqrt{2}}\)A1 Allow \(\pm\)
Form equation in \(\lambda\): \((2\lambda^2 + .4\lambda - 0.96 = 0)\)DM1 e.g. by use of cosine rule. Dependent on the first 2 M marks
\(\lambda = \dfrac{3}{5}\) or \(\lambda = -\dfrac{4}{5}\)A1 Or equivalent
Total: (6)
# Question 3:

| Answer/Working | Mark | Guidance |
|---|---|---|
| Use of $\mathbf{I} = m\mathbf{v} - m\mathbf{u}$ | M1 | Accept equivalent e.g. $\mathbf{I}+m\mathbf{u}=m\mathbf{v}$. Dimensionally correct, must be using subtraction. Use of 7 in place of velocity in impulse-momentum equation is M0 unless they recover |
| $0.2(\mathbf{v} - 4\mathbf{i} + 3\mathbf{j}) = \lambda(\mathbf{i}+\mathbf{j})$ leading to $((x-4)\mathbf{i}+(y+3)\mathbf{j} = 5\lambda\mathbf{i}+5\lambda\mathbf{j})$ | A1 | Correct unsimplified vector equation or pair of separate equations for $\mathbf{i}$ and $\mathbf{j}$ components. Condone column vectors |
| Use of Pythagoras for the speed | M1 | Correct use of Pythagoras and 49 for their speed |
| $x^2 + y^2 = 49$ | A1 | Correct unsimplified equation for their $x$, $y$ |
| Form quadratic in $x$, $y$ or $\lambda$ and solve for $\lambda$ | DM1 | Dependent on both previous M marks. $x^2 + -(x-7)^2 = 49$ or $(y+7)^2 + y^2 = 49$ or $(5\lambda+4)^2 + (5\lambda-3)^2 = 49$ |
| $\lambda = \dfrac{3}{5}$ or $\lambda = -\dfrac{4}{5}$ | A1 | Or equivalent |
| **Total: (6)** | | |

### Alternative Method (Question 3):
| Answer/Working | Mark | Guidance |
|---|---|---|
| Form vector triangle | M1 | Dimensionally correct. Allow incorrect configuration |
| Correct triangle and correct lengths | A1 | In speeds or momentum but not a mixture |
| Use scalar product to find cosine of angle | M1 | Or equivalent method |
| $\cos\theta = -\dfrac{1}{5\sqrt{2}}$ | A1 | Allow $\pm$ |
| Form equation in $\lambda$: $(2\lambda^2 + .4\lambda - 0.96 = 0)$ | DM1 | e.g. by use of cosine rule. Dependent on the first 2 M marks |
| $\lambda = \dfrac{3}{5}$ or $\lambda = -\dfrac{4}{5}$ | A1 | Or equivalent |
| **Total: (6)** | | |

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\begin{enumerate}
  \item A particle $P$ of mass 0.2 kg is moving with velocity $( 4 \mathbf { i } - 3 \mathbf { j } ) \mathrm { ms } ^ { - 1 }$
\end{enumerate}

The particle receives an impulse $\lambda ( \mathbf { i } + \mathbf { j } ) \mathrm { Ns }$, where $\lambda$ is a constant.\\
Immediately after receiving the impulse, the speed of $P$ is $7 \mathrm {~m} \mathrm {~s} ^ { - 1 }$\\
Find the possible values of $\lambda$

\hfill \mbox{\textit{Edexcel M2 2022 Q3 [6]}}