CAIE P2 2011 June — Question 2 5 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2011
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeDeduce related integral from numerical approximation
DifficultyStandard +0.3 Part (i) is a straightforward application of the trapezium rule with clear intervals. Part (ii) requires recognizing that region B can be found by subtracting region A from a rectangle (2×3), then explaining the geometric reason for underestimation—this involves some insight but is a standard technique for relating areas. The question tests understanding beyond mechanical calculation but remains accessible for P2 level.
Spec1.09f Trapezium rule: numerical integration

2 \includegraphics[max width=\textwidth, alt={}, center]{2c27f384-5289-4c1b-9199-6b4c6ac81e38-2_645_750_429_699} The diagram shows the curve \(y = \sqrt { } \left( 1 + x ^ { 3 } \right)\). Region \(A\) is bounded by the curve and the lines \(x = 0\), \(x = 2\) and \(y = 0\). Region \(B\) is bounded by the curve and the lines \(x = 0\) and \(y = 3\).
  1. Use the trapezium rule with two intervals to find an approximation to the area of region \(A\). Give your answer correct to 2 decimal places.
  2. Deduce an approximation to the area of region \(B\) and explain why this approximation underestimates the true area of region \(B\).

AnswerMarks Guidance
(i) Show or imply correct ordinates \(1, \sqrt{2}\) or \(1.414, 3\)B1
Use correct formula, or equivalent, with \(h = 1\)M1
Obtain \(3.41\)A1 [3]
(ii) Obtain \(6 - 3.41\) and hence \(2.59\), following their answer to (i) provided less than \(6\)B1√
Refer, in some form, to two line segments replacing curve and conclude with clear justification of given result that answer is an under-estimateB1 [2]
**(i)** Show or imply correct ordinates $1, \sqrt{2}$ or $1.414, 3$ | B1 |
Use correct formula, or equivalent, with $h = 1$ | M1 |
Obtain $3.41$ | A1 | [3]

**(ii)** Obtain $6 - 3.41$ and hence $2.59$, following their answer to (i) provided less than $6$ | B1√ |
Refer, in some form, to two line segments replacing curve and conclude with clear justification of given result that answer is an under-estimate | B1 | [2]
2\\
\includegraphics[max width=\textwidth, alt={}, center]{2c27f384-5289-4c1b-9199-6b4c6ac81e38-2_645_750_429_699}

The diagram shows the curve $y = \sqrt { } \left( 1 + x ^ { 3 } \right)$. Region $A$ is bounded by the curve and the lines $x = 0$, $x = 2$ and $y = 0$. Region $B$ is bounded by the curve and the lines $x = 0$ and $y = 3$.\\
(i) Use the trapezium rule with two intervals to find an approximation to the area of region $A$. Give your answer correct to 2 decimal places.\\
(ii) Deduce an approximation to the area of region $B$ and explain why this approximation underestimates the true area of region $B$.

\hfill \mbox{\textit{CAIE P2 2011 Q2 [5]}}