Easy -1.2 This is a straightforward recurrence relation requiring only direct substitution and basic fraction arithmetic. Students simply apply the given formula three times with no problem-solving or insight needed—purely mechanical calculation that's easier than typical A-level questions.
6 You are given that
$$\begin{aligned}
u _ { 1 } & = 1 \\
u _ { n + 1 } & = \frac { u _ { n } } { 1 + u _ { n } }
\end{aligned}$$
Find the values of \(u _ { 2 } , u _ { 3 }\) and \(u _ { 4 }\). Give your answers as fractions.
6 You are given that
$$\begin{aligned}
u _ { 1 } & = 1 \\
u _ { n + 1 } & = \frac { u _ { n } } { 1 + u _ { n } }
\end{aligned}$$
Find the values of $u _ { 2 } , u _ { 3 }$ and $u _ { 4 }$. Give your answers as fractions.
\hfill \mbox{\textit{OCR MEI C2 Q6 [2]}}