| Exam Board | OCR MEI |
|---|---|
| Module | C2 (Core Mathematics 2) |
| Marks | 12 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Arithmetic Sequences and Series |
| Type | Real-world AP: find term or total |
| Difficulty | Moderate -0.3 This is a straightforward multi-part question testing standard arithmetic sequence formulas (part a) and basic geometric progression properties including sum to infinity and logarithmic manipulation (part b). All techniques are routine C2 level with clear scaffolding - slightly easier than average due to the step-by-step guidance and standard textbook methods required. |
| Spec | 1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<11.06f Laws of logarithms: addition, subtraction, power rules |
| Answer | Marks |
|---|---|
| \(13\) | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| \(120\) | M1, A1 | M1 for attempt at AP formula ft their \(a\), \(d\) or for \(3 + 5 + \ldots + 21\) |
| Answer | Marks | Guidance |
|---|---|---|
| \(\dfrac{125}{1296}\) | M1, A1 | M1 for \(\dfrac{1}{6} \times \left(\dfrac{5}{6}\right)^3\) |
| Answer | Marks | Guidance |
|---|---|---|
| \(a = 1/6,\ r = 5/6\) s.o.i. | B1, B1 | If not specified, must be in right order |
| \(S_{\infty} = \dfrac{\frac{1}{6}}{1 - \frac{5}{6}}\) o. | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| \(\left(\dfrac{5}{6}\right)^{n-1} < 0.006\) | M1 | |
| \((n-1)\log_{10}\left(\dfrac{5}{6}\right) < \log_{10} 0.006\) | M1 | condone omission of base, but not brackets |
| \(n - 1 > \dfrac{\log_{10} 0.006}{\log_{10}\left(\dfrac{5}{6}\right)}\) | DM1 | |
| \(n_{\min} = 30\) | B1 | NB change of sign must come at correct place |
| Or: \(\log(1/6) + \log(5/6)^{n-1} < \log 0.001\) | M1 | |
| \((n-1)\log(5/6) < \log(0.001/(1/6))\) | M1 |
## Question 4:
### Part ai:
$13$ | B1 | |
### Part aii:
$120$ | M1, A1 | M1 for attempt at AP formula ft their $a$, $d$ or for $3 + 5 + \ldots + 21$ |
### Part bi:
$\dfrac{125}{1296}$ | M1, A1 | M1 for $\dfrac{1}{6} \times \left(\dfrac{5}{6}\right)^3$ |
### Part bii:
$a = 1/6,\ r = 5/6$ s.o.i. | B1, B1 | If not specified, must be in right order |
$S_{\infty} = \dfrac{\frac{1}{6}}{1 - \frac{5}{6}}$ o. | B1 | |
### Part biii:
$\left(\dfrac{5}{6}\right)^{n-1} < 0.006$ | M1 | |
$(n-1)\log_{10}\left(\dfrac{5}{6}\right) < \log_{10} 0.006$ | M1 | condone omission of base, but not brackets |
$n - 1 > \dfrac{\log_{10} 0.006}{\log_{10}\left(\dfrac{5}{6}\right)}$ | DM1 | |
$n_{\min} = 30$ | B1 | NB change of sign must come at correct place |
Or: $\log(1/6) + \log(5/6)^{n-1} < \log 0.001$ | M1 | |
$(n-1)\log(5/6) < \log(0.001/(1/6))$ | M1 | |
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4
\begin{enumerate}[label=(\alph*)]
\item André is playing a game where he makes piles of counters. He puts 3 counters in the first pile. Each successive pile he makes has 2 more counters in it than the previous one.
\begin{enumerate}[label=(\roman*)]
\item How many counters are there in his sixth pile?
\item André makes ten piles of counters. How many counters has he used altogether?
\end{enumerate}\item In another game, played with an ordinary fair die and counters, Betty needs to throw a six to start.
The probability $\mathrm { P } _ { n }$ of Betty starting on her $n$th throw is given by
$$P _ { n } = \frac { 1 } { 6 } \times \left( \frac { 5 } { 6 } \right) ^ { n - 1 }$$
\begin{enumerate}[label=(\roman*)]
\item Calculate $\mathrm { P } _ { 4 }$. Give your answer as a fraction.
\item The values $\mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } , \mathrm { P } _ { 3 } , \ldots$ form an infinite geometric progression. State the first term and the common ratio of this progression.
Hence show that $\mathrm { P } _ { 1 } + \mathrm { P } _ { 2 } + \mathrm { P } _ { 3 } + \ldots = 1$.
\item Given that $\mathrm { P } _ { n } < 0.001$, show that $n$ satisfies the inequality
$$n > \frac { \log _ { 10 } 0.006 } { \log _ { 10 } \left( \frac { 5 } { 6 } \right) } + 1$$
Hence find the least value of $n$ for which $\mathrm { P } _ { n } < 0.001$.
\end{enumerate}\end{enumerate}
\hfill \mbox{\textit{OCR MEI C2 Q4 [12]}}