OCR C3 — Question 3 6 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeSolve equation with reciprocal functions
DifficultyStandard +0.3 This is a standard reciprocal trig equation requiring the Pythagorean identity cot²y + 1 = cosec²y to convert to a quadratic in cosec y, then solving and finding angles. It's slightly above average difficulty due to using less common reciprocal functions, but follows a routine procedure taught in C3 with no novel insight required.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05o Trigonometric equations: solve in given intervals

3. Solve, for \(0 \leq y \leq 360\), the equation $$2 \cot ^ { 2 } y ^ { \circ } + 5 \operatorname { cosec } y ^ { \circ } + \operatorname { cosec } ^ { 2 } y ^ { \circ } = 0$$

3. Solve, for $0 \leq y \leq 360$, the equation

$$2 \cot ^ { 2 } y ^ { \circ } + 5 \operatorname { cosec } y ^ { \circ } + \operatorname { cosec } ^ { 2 } y ^ { \circ } = 0$$

\hfill \mbox{\textit{OCR C3  Q3 [6]}}