OCR C3 — Question 1 5 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSolve |linear| < constant with sketch or follow-up application
DifficultyStandard +0.3 Part (i) is a routine modulus inequality requiring simple manipulation to get 0.17 < x < 0.23. Part (ii) requires substituting x = 0.95^n and solving logarithmically, which adds a modest step beyond standard textbook exercises but remains straightforward application of techniques.
Spec1.02h Express solutions: using 'and', 'or', set and interval notation1.02l Modulus function: notation, relations, equations and inequalities

  1. (i) Solve the inequality
$$| x - 0.2 | < 0.03$$ (ii) Hence, find all integers \(n\) such that $$\left| 0.95 ^ { n } - 0.2 \right| < 0.03$$

\begin{enumerate}
  \item (i) Solve the inequality
\end{enumerate}

$$| x - 0.2 | < 0.03$$

(ii) Hence, find all integers $n$ such that

$$\left| 0.95 ^ { n } - 0.2 \right| < 0.03$$

\hfill \mbox{\textit{OCR C3  Q1 [5]}}