OCR MEI C2 — Question 5 5 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeFind stationary points coordinates
DifficultyModerate -0.3 This is a straightforward C2 differentiation question requiring standard techniques: differentiating polynomials and reciprocals, finding stationary points by setting dy/dx=0, identifying decreasing intervals, and finding tangent equations. All steps are routine textbook exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx

5 Differentiate \(4 x ^ { 2 } + \frac { 1 } { x }\) and hence find the \(x\)-coordinate of the stationary point of the curve \(y = 4 x ^ { 2 } + \frac { 1 } { x }\). \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{bba82ee6-90b2-4f03-9bb9-0371ff711a09-3_639_1027_302_542} \captionsetup{labelformat=empty} \caption{Fig. 11}
\end{figure} The equation of the curve shown in Fig. 11 is \(y = x ^ { 3 } - 6 x + 2\).
  1. Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\).
  2. Find, in exact form, the range of values of \(x\) for which \(x ^ { 3 } - 6 x + 2\) is a decreasing function.
  3. Find the equation of the tangent to the curve at the point \(( - 1,7 )\). Find also the coordinates of the point where this tangent crosses the curve again.

Question 5:
AnswerMarks Guidance
AnswerMark Guidance
[two terms differentiated]B1, B1 B1 each term
their \(\dfrac{dy}{dx} = 0\)M1 s.o.i.
correct stepDM1 s.o.i.
\(x = \frac{1}{2}\) c.a.o.A1
[5 marks]
## Question 5:

| Answer | Mark | Guidance |
|--------|------|----------|
| [two terms differentiated] | B1, B1 | B1 each term |
| their $\dfrac{dy}{dx} = 0$ | M1 | s.o.i. |
| correct step | DM1 | s.o.i. |
| $x = \frac{1}{2}$ c.a.o. | A1 | |

**[5 marks]**

---
5 Differentiate $4 x ^ { 2 } + \frac { 1 } { x }$ and hence find the $x$-coordinate of the stationary point of the curve $y = 4 x ^ { 2 } + \frac { 1 } { x }$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{bba82ee6-90b2-4f03-9bb9-0371ff711a09-3_639_1027_302_542}
\captionsetup{labelformat=empty}
\caption{Fig. 11}
\end{center}
\end{figure}

The equation of the curve shown in Fig. 11 is $y = x ^ { 3 } - 6 x + 2$.\\
(i) Find $\frac { \mathrm { d } y } { \mathrm {~d} x }$.\\
(ii) Find, in exact form, the range of values of $x$ for which $x ^ { 3 } - 6 x + 2$ is a decreasing function.\\
(iii) Find the equation of the tangent to the curve at the point $( - 1,7 )$.

Find also the coordinates of the point where this tangent crosses the curve again.

\hfill \mbox{\textit{OCR MEI C2  Q5 [5]}}