| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2010 |
| Session | January |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Newton's second law with vector forces (find acceleration or force) |
| Difficulty | Moderate -0.8 This is a straightforward application of constant acceleration kinematics in 2D vectors followed by Newton's second law (F=ma). All three parts use standard formulas with direct substitution: (i) a = (v-u)/t, (ii) s = ut + ½at², (iii) F = ma. No problem-solving insight required, just routine calculation with vectors, making it easier than average. |
| Spec | 3.02e Two-dimensional constant acceleration: with vectors3.03c Newton's second law: F=ma one dimension |
2 A particle of mass 5 kg has constant acceleration. Initially, the particle is at $\binom { - 1 } { 2 } \mathrm {~m}$ with velocity $\binom { 2 } { - 3 } \mathrm {~m} \mathrm {~s} ^ { - 1 }$; after 4 seconds the particle has velocity $\binom { 12 } { 9 } \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(i) Calculate the acceleration of the particle.\\
(ii) Calculate the position of the particle at the end of the 4 seconds.\\
(iii) Calculate the force acting on the particle.
\hfill \mbox{\textit{OCR MEI M1 2010 Q2 [7]}}