OCR MEI M1 2005 January — Question 1 7 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Year2005
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVariable acceleration (vectors)
TypeFind force using F=ma
DifficultyModerate -0.8 This is a straightforward mechanics question requiring only routine differentiation of a position vector twice to find acceleration, then direct application of F=ma. Both parts are standard textbook exercises with no problem-solving or insight required—simpler than average A-level questions.
Spec3.02g Two-dimensional variable acceleration3.03d Newton's second law: 2D vectors

1 The position vector, \(\mathbf { r }\), of a particle of mass 4 kg at time \(t\) is given by $$\mathbf { r } = t ^ { 2 } \mathbf { i } + \left( 5 t - 2 t ^ { 2 } \right) \mathbf { j } ,$$ where \(\mathbf { i }\) and \(\mathbf { j }\) are the standard unit vectors, lengths are in metres and time is in seconds.
  1. Find an expression for the acceleration of the particle. The particle is subject to a force \(\mathbf { F }\) and a force \(12 \mathbf { j } \mathbf { N }\).
  2. Find \(\mathbf { F }\).

Part (i)
AnswerMarks Guidance
Differentiate \(v = 2ti + (5 - 4t)j\)M1 At least 1 cpt correct
A1Award for RHS seen
Differentiate \(a = 2i - 4j\)M1 Do not award if \(i\) and \(j\) lost in \(v\). At least 1 cpt correct. FT FT from their 2 component \(v\)
Total: 4
Part (ii)
AnswerMarks Guidance
\(\mathbf{F} + 12j = 4(2i - 4j)\)M1 N2L. Allow \(F = mg a\). No extra forces. Allow 12j omitted
A1Allow wrong signs otherwise correct with their vector \(a\)
\(\mathbf{F} = 8i - 28j\)A1 cao
Total: 3
**Part (i)**

| Differentiate $v = 2ti + (5 - 4t)j$ | M1 | At least 1 cpt correct |
|---|---|---|
| | A1 | Award for RHS seen |
| Differentiate $a = 2i - 4j$ | M1 | Do not award if $i$ and $j$ lost in $v$. At least 1 cpt correct. FT FT from their 2 component $v$ |
| | | **Total: 4** |

**Part (ii)**

| $\mathbf{F} + 12j = 4(2i - 4j)$ | M1 | N2L. Allow $F = mg a$. No extra forces. Allow 12j omitted |
| | A1 | Allow wrong signs otherwise correct with their vector $a$ |
| $\mathbf{F} = 8i - 28j$ | A1 | cao |
| | | **Total: 3** |

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1 The position vector, $\mathbf { r }$, of a particle of mass 4 kg at time $t$ is given by

$$\mathbf { r } = t ^ { 2 } \mathbf { i } + \left( 5 t - 2 t ^ { 2 } \right) \mathbf { j } ,$$

where $\mathbf { i }$ and $\mathbf { j }$ are the standard unit vectors, lengths are in metres and time is in seconds.\\
(i) Find an expression for the acceleration of the particle.

The particle is subject to a force $\mathbf { F }$ and a force $12 \mathbf { j } \mathbf { N }$.\\
(ii) Find $\mathbf { F }$.

\hfill \mbox{\textit{OCR MEI M1 2005 Q1 [7]}}