6.
$$f ( x ) = 2 x ^ { 3 } + 3 x ^ { 2 } - 6 x + 1$$
- Find the remainder when \(\mathrm { f } ( x )\) is divided by ( \(2 x - 1\) ).
- Find the remainder when \(\mathrm { f } ( x )\) is divided by \(( x + 2 )\).
- Hence, or otherwise, solve the equation
$$2 x ^ { 3 } + 3 x ^ { 2 } - 6 x - 8 = 0$$